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lions [1.4K]
3 years ago
9

Transverse waves are sent along a 4.50 m long string with a speed of 85.00 m/s. The string is under a tension of 20.00 N. What i

s the mass of the string (in kg)?
Physics
1 answer:
frutty [35]3 years ago
5 0

Answer:

m = 0.0125 kg

Explanation:

Let us apply the formula for the speed of a wave on a string that is under tension:

v = \sqrt{\frac{F}{\mu} }

where F = tension force

μ = mass per unit length

Mass per unit length is given as:

μ  = m / l

where m = mass of the string

l = length of the string

This implies that:

v = \sqrt{\frac{F}{m/l} }\\ \\v = \sqrt{\frac{F * l}{m} }

Let us make mass, m, the subject of the formula:

v^2 = \frac{F * l}{m}\\\\m = \frac{F * l}{v^2}

From the question:

F = 20 N

l = 4.50 m

v = 85 m/s

Therefore:

m = \frac{20 * 4.5}{85^2}\\\\m = \frac{90}{7225}\\ \\m = 0.0125 kg

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2 years ago
Mary and her younger brother Alex decide to ride the carousel at the State Fair. Mary sits on one of the horses in the outer sec
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Answer:

ωM = 1.7 rad/s

vM = 3.4 m/s

ωA = 1.7 rad/s

vA =  1.7  m/s

Explanation:

Calculation of the angular speed (ω)

We use the following formula for circular motion:

ω = θ / t Formula (1)

Where:

ω: angular speed (rad/s)

θ:angle that the particle travels (rad)

t: time interval (s)

Equivalence

1 revolution = 2π rad

Data

θ= 1 revolution = 2π rad

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We replace data in the formula (1):

ω = (2π rad) / (3.7s )= 1.7 rad/s

Because the angular speed depends only on the number of turns in a time interval then Mary's angular speed (ωM) is equal to Alex's angular speed (ωA).

ωM = ωA = 1.7 rad/s

Calculation of the  tangential speed (v)

We use the following formula for circular motion:

v = ω*r  Formula (2)

Where:

v : tangential speed (m/s)

ω: angular speed ( rad/s)

r  : radius of the circular path (m)

Data

ωM = ωM = ω= 1.7 rad/s

rM = 2m  : Mary's circular path radius

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We apply the formula (2) to calculate v:

vM = ω* rM = (1.7) (2) = 3.4 m/s

vA = ω* rA = (1.7) (1) =  1.7  m/s

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