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snow_tiger [21]
3 years ago
15

Does CuNO2. contain a polytomic ion

Chemistry
1 answer:
devlian [24]3 years ago
5 0
I don’t know sorry i had to answer something so i could use this account still
You might be interested in
How many molecules of carbon dioxide are in 5.61 moles of carbon dioxide (CO2)?
gulaghasi [49]
<h3>Answer:</h3>

3.38 × 10²⁴ molecules CO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 5.61 moles CO₂

[Solve] molecules CO₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 5.61 \ mooles \ CO_2(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 3.37834 \cdot 10^{24} \ molecules \ CO_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.37834 × 10²⁴ molecules CO₂ ≈ 3.38 × 10²⁴ molecules CO₂

6 0
3 years ago
A 76 pound flask a mercury cost $126 the density and mercury is 13.534 g/cm³ find the price of one cubic inch of mercury by calc
swat32
To determine the cost of the mercury per cubic inch, we need to divide the total cost with the total volume in units of cubic inches. To do this, we first determine the volume of the mercury given the mass and the density. In any operation, it is important to remember that the units of the values involved should be homogeneous so that we can cancel them. We do as follows:

mass of mercury = 76 lb ( 1 kg / 2.2 lbs ) ( 1000 g / 1 kg ) = 34545.45 g
volume of mercury in cm^3 = 34545.45 g / 13.534 g / cm^3 = 2552.49 cm^3

We need to convert this to units of cubic inches since it is what is asked.

volume of mercury in in^3 = 2552.49 cm^3 ( 1 in / 2.54 cm )^3 = 155.76 in^3
cost per in^3 = $126 / 155.76 in^3 = $ 0.809 / in^3
3 0
3 years ago
Pieces of dry ice become smaller through the process of condensation. true or false.
stiv31 [10]
Totally false. There is no process of condensation for dry ice as it either sublimes from dry ice to co2 or sublime back to dry ice
3 0
3 years ago
A basketball weighs approximately 1.35 kg. What is this mass in grams (g)?<br><br> step by step
choli [55]

Answer:

1350 g

Explanation: just add a 0

8 0
3 years ago
Figure the molar mass of aluminum sulfate to the nearest gram
Brilliant_brown [7]
Should be that answer
342 gram

8 0
3 years ago
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