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Katena32 [7]
3 years ago
10

Which complex ion can exhibit geometric isomerism? Assume that M is the metal ion, A and B are ligands, and the geometry is octa

hedral. a) [MA.12+ b) [MAB]2+ c) [MA4B2]2+ d) [MA3B312+
Chemistry
1 answer:
Archy [21]3 years ago
7 0

Answer:

[MA4B2]2+

Explanation:

Octahedral species are species that has a coordination number of of six. This means that six ligands are attached to the central metal atom/ion.

For any octahedral specie to exhibit geometrical or cis-trans isomerism, it must have the formula EX2Y4 as in [MA4B2]2+, hence the answer above.

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How does the vegetation surface type affect the amount of runoff
maxonik [38]

Answer:

<em>The type of vegetation a surface does affect the </em><em>water coming from above to sink in or runoff. </em>

Explanation:

This is how the vegetation affects the runoff:-

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3 years ago
How to solve x² in differential​
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Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu
pochemuha

Answer : The volume of CO_2 will be, 514.11 ml

Explanation :

The balanced chemical reaction will be,

HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2

First we have to calculate the  mass of HCO_3^- in tablet.

\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g

Now we have to calculate the moles of HCO_3^-.

Molar mass of HCO_3^- = 1 + 12 + 3(16) = 61 g/mole

\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles

Now we have to calculate the moles of CO_2.

From the balanced chemical reaction, we conclude that

As, 1 mole of HCO_3^- react to give 1 mole of CO_2

So, 0.0202 mole of HCO_3^- react to give 0.0202 mole of CO_2

The moles of CO_2 = 0.0202 mole

Now we have to calculate the volume of CO_2 by using ideal gas equation.

PV=nRT

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = 37^oC=273+37=310K

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)

V=0.51411L=514.11ml

Therefore, the volume of CO_2 will be, 514.11 ml

6 0
3 years ago
Wolff-kishner reduction (hydrazine, koh, ethylene glycol, 130°c) of the compound shown gave compound
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Step three: Reduction:
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Step four: Oxidation:
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8 0
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