Answer:
λ = 0.002 nm
The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.
Explanation:
Given data:
Energy of photon = 1.10 × 10⁻¹³ J.
Wavelength of photon = ?
Solution:
Formula:
E = h.c / λ
λ = h. c / E
λ = 6.626 × 10⁻³⁴ j. s × 3×10⁸ m/s / 1.10 × 10⁻¹³ J.
λ = 19.878 × 10⁻²⁶m / 1.10 × 10⁻¹³ J
λ = 18.071 × 10⁻¹³ m
λ = 18.071 × 10⁻¹³ × 10⁹
λ = 18.071 × 10⁻⁴ nm
λ = 0.002 nm
The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.
The pH of the solution is 3,76
Why?
To solve this problem we have to apply the Henderson-Hasselbach equation, which is used whenever we need to calculate the pH of a solution of an acid HA (Lactic Acid) and its conjugate base A⁻ (Sodium Lactate)
We can use either moles or concentrations for this equation. In this case, we are going to use the moles, and we are going to take the pKa of lactic acid as 3,86:
Have a nice day!
#LearnwithBrainly
Answer: 
is the correct equation for beta decay.
Explanation:
When a beta particle, that is, 
is emitted in a radioactive decay then it is known as beta decay.
Therefore, beta decay of Polonium-218 is as follows.
Therefore, we can conclude that is the correct equation for the given beta decay.
The most common way of preventing bumping is by adding one or two boiling chips to the reaction vessel. However, these alone may not prevent bumping and for this reason it is advisable to boil liquids in a boiling tube, a boiling flask, or an Erlenmeyer flask.
Na5Cl2
penta is 5, so 5 sodiums and di is 2, so 2 chloride
