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Sergeeva-Olga [200]
3 years ago
11

What is the difference between the absolute value of -8 and the absolue value of 6? O 2 O8 O 14 O 16​

Mathematics
1 answer:
Lisa [10]3 years ago
4 0

Answer:

  • A. 2

Step-by-step explanation:

<u>Absolute value is always positive:</u>

  • |-8| = 8
  • |6| = 6

<u>Their difference is:</u>

  • 8 - 6 = 2

Correct choice is A

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I'm gonna go with triangle B. Triangles A,C,and E all look to be somewhat congruent in that they're all equilateral. Triangle D and F look similar but Triangle b looks like its isosceles and the others aren't like that.
8 0
4 years ago
WILL SOMEONE HELP ME ANSWER THIS PLEASE!!!!
Korolek [52]

l+w=20000

l=w+4000

w+4000+w=20000

2w+4000=20000

2w=16000

w=8000

l = 8000 +4000 = 12000


William scored 8000, Luca scored 12000

3 0
3 years ago
Read 2 more answers
7. By using binomial expansion show that the value of (1.01)^12 exceed the value of (1.02)^6 by 0.0007 correct to four decimal p
BlackZzzverrR [31]

Binomial expansion is used to factor expressions that can be expressed as the power of the sum of two numbers.

The proof that (1.01)^12 exceeds (1.02)^6 by 0.0007 is\mathbf{(1.01)^{12} - (1.02)^6 \approx 0.0007 }

The expressions are given as:

\mathbf{(1.01)^{12}\ and\ (1.02)^6}

A binomial expression is represented as:

\mathbf{(a + b)^n = \sum\limits^n_{k=0}^nC_k a^{n - k}b^k}

Express 1.01 as 1 + 0.01

So, we have:

\mathbf{(1.01)^{12} = (1 + 0.01)^{12}}

Apply the above formula

\mathbf{(1.01)^{12} = ^{12}C_0 \times 1^{12 - 0} \times 0.01^0 + .........  .......... +  ^{12}C_{12} \times 1^{12 - 12} \times 0.01^{12} }}

\mathbf{(1.01)^{12} = 1 \times 1 \times 1 + .........  .......... +  1 \times 1 \times 10^{-24} }}

\mathbf{(1.01)^{12} = 1  + .........  .......... +  10^{-24} }}

This gives

\mathbf{(1.01)^{12} = 1.1268\ (approximated)}

Similarly,

Express 1.02 as 1 + 0.02

So, we have:

\mathbf{(1.02)^6 = (1 + 0.02)^6}

Apply \mathbf{(a + b)^n = \sum\limits^n_{k=0}^nC_k a^{n - k}b^k}

\mathbf{(1.02)^6 = ^6C_0 \times 1^{6 - 0} \times 0.02^0 +  ^6C_1 \times 1^{6 - 1} \times 0.02^1 +.............. + ^6C_6 \times 1^{6 - 6} \times 0.02^6 }\mathbf{(1.02)^6 = 1 \times 1 \times 1 +  6 \times 1 \times 0.02 +.............. + 1 \times 1 \times 6.4 \times 10^{-11} }

\mathbf{(1.02)^6 = 1 +  0.12 +.............. + 6.4 \times 10^{-11} }

This gives

\mathbf{(1.02)^6 = 1.1261\ (approximated) }

Calculate the difference as follows:

\mathbf{(1.01)^{12} - (1.02)^6 \approx 1.1268 - 1.1261 }

\mathbf{(1.01)^{12} - (1.02)^6 \approx 0.0007 }

The above equation means that:

(1.01)^12 exceed the value of (1.02)^6 by 0.0007

Read more about binomial expansions at:

brainly.com/question/9554282

7 0
3 years ago
A line passes through the point (-8,7) and has a
zaharov [31]

Answer:

y = (-5/2)x + 27

Step-by-step explanation:

Use the point slope formula y = mx + b.

Replace m with -5/2, x with -8 and y with 7:

7 = (-5/2)(8) + b.  Find the y-intercept, b:

7 = -20 = b, or b = 27

The equation of this line is y = (-5/2)x + 27.

6 0
3 years ago
Jamel and his sister received a total of $250 for their birthday. If Jamel received $30 less than his sister, how much did each
alexandr402 [8]

Answer:

Jamel - 110 Sister - 140

Step-by-step explanation:

We are going to work backwards. If Jamel received 30 dollars less than his sister, then the total goes down to $220. Then you divide by 2 to split the money between each equally. Now Jamel has $110 and his sister has $110. But you have to add the original $30 back to his sister's total because she got  $30 more. Hence Jamel has $110 and his sister has $140.

5 0
3 years ago
Read 2 more answers
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