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3 years ago

So what is the answer

Mathematics

1 answer:

Zarrin [17]3 years ago

5 0

There is no question and and therefore cannot be answered

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A cylindrical cardboard mailing tube has a diameter of 5 in. and a height of 30 in. A total of 30% of the tube’s capacity is fil

olga2289 [7]

First is to get the volume of the cylinder.
Volume = pi * r^2 * H
Volume = 3.1416 * (5/2)^2 * 30
Volume = 589.05 in^3

30% is already filled.
Filled Space = 589.05 * 0.30
Filled Space = 176.715 in^3
Empty Space = 412.335 in^3

Next, get the volume of the sphere.
V = (4/3)*pi*r^3
V = (4/3)*pi*(0.6/2)^3
V = 0.1130976 in^3

Number of foams = Filled Space / V
Number of foams = 176.715 / 0.1130976
Number of foams = 1562 Foams

5 0

3 years ago

In a cafeteria, 100 milk cartons were put out for breakfast. After breakfast there were 40 milk cartons left. What is the ratio

VMariaS [17]

the ratio would be 40:60

3 0

3 years ago

Read 2 more answers

Identify the translations of the graph of the parent function f(x) = x^2? that result in the graph of g(x) = (x + 2)2 + 6.

Anna [14]

Answer:

Step-by-step explanation: bacause if you see and look really close

3 0

2 years ago

Which number sentence is true? A. –7 + 10 = –3 B. –7 – (–10) = –17 C. 7 – 10 = 3 D. 7 – (–10) = 17

Mice21 [21]

Assignment: $\bold{Which \ Statement \ Is \ True}$

<><><><><>

Answer: $\boxed{\bold{7-\left(-10\right)}}$

<><><><><>

Explanation: $\downarrow\downarrow\downarrow$

<><><><><>

Note: $\bold{Solve \ Equation \ To \ Find \ Answer}$

[ Step One ] Apply Rule - (-a) = a

$\bold{7+10}$

[ Step Two ] Add

$\bold{17}$

<><><><><><><>

$\bold{\rightarrow Rhythm \ Bot \leftarrow}$

3 0

3 years ago

Read 2 more answers

Help. I need help with these questions ( see image). Please show workings.

Andrew [12]

9514 1404 393

Answer:

4) 6x

5) 2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

$\text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}$

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the power rule.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

lim[h→0](f(x+h)-f(x))/h = 2ax +b

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0

3 years ago