3 years ago

Please helpp!! Questions 1-5

Physics

1 answer:

Fofino [41]3 years ago

6 0

Answer:

A:Time (minutes)

B: Temp(degrees c)

2. Downward trend (temperature goes down as time goes on )

A: not sure

B: temperature

4.the temperature is going down

5. Closes off any open airways

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Calculate the resistance of an electric bulb which allows a 10 A current when connected to a 220 V power source

kodGreya [7K]

Resistance can be calculated by Ohm's law

As per ohm's law we will have

$V = i * R$

here we will have

voltage = 220 volts

current = 10 A

So by the above formula we will have

$220 = 10* R$

$R = 22 ohm$

So resistance of the bulb is 22 ohm.

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4 years ago

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60 = ?
300 × 60 ÷ 38
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3 years ago

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Vlad1618 [11]

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3 years ago

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One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching this

Afina-wow [57]

Answer: $27^{\circ}$

Explanation:

Given

Initial velocity of both snowball is 29.3 m/s

first snowball launch angle $=63^{\circ}$

Considering motion of snowball to be projectile

range is given by

$R=\frac{u^2\sin 2\theta }{g}$

$R=\frac{29.3^2\sin 126}{9.8}$

R=70.87 m-----1

If second snowball is thrown at an angle of \phi

$R=\frac{u^2\sin 2\phi }{g}$

$R=\frac{29.3^2\sin 2\phi }{9.8}$ ------2

$70.87=87.601\sin 2\phi$

$0.809=\sin \phi$

$2\phi can be 53.99^{\circ}$

or $180-2\phi =53.99^{\circ}$

Thus $\phi =26.995 \approx 27^{\circ}$

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3 years ago