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Troyanec [42]
3 years ago
12

Simplify the radical expression square root of 64y^10h^5/16y^12h^5

Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0
We assume the variables y and h to be positive.

\sqrt{\dfrac{64y^{10}h^{5}}{16y^{12}h^{5}}} =

= \sqrt{\dfrac{64}{16} \times \dfrac{y^{10}}{y^{12}} \times \dfrac{h^{5}}{h^{5}}}

= \sqrt{4 \times \dfrac{1}{y^{2}} \times 1}

= \sqrt{\dfrac{4}{y^{2}}}

= \dfrac{2}{y}
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Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let c(t) is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt

\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0

\int\limits^{20}_{0} {c'(t)} \, dt =3600+600

\int\limits^{20}_{0} {c'(t)} \, dt =4200

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

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Can someone please help me with this, it is due tomorrow and I don’t get it.
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for the volume do the equation length×width×height. so 10×4×2.75

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Step-by-step explanation:

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3 years ago
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