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yuradex [85]
4 years ago
15

What is the equation used to calculate power?

Physics
2 answers:
shtirl [24]4 years ago
6 0

Answer:

Power = Work ÷ Time

( Watts ) = ( Joules ) ÷ ( Seconds )

Explanation:

Paladinen [302]4 years ago
3 0

Answer:

p =  \frac{w}{t}  \\    p = power(watts) \\ w = work(joules) \\ t = time(seconds)

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Which of these does not separate WhiteLight into the colors of the visible spectrum?
salantis [7]

Answer:

A. rods in the retina of the human eye

Explanation:

6 0
4 years ago
You are walking around your neighborhood and you see a child on top of a roof of a building kick a soccer ball. The soccer ball
const2013 [10]

Answer:

The building is 61.19 m tall, approximately.

Explanation:

From the parabollic movement trayectory equation,

y=H+\frac{v_{0y}}{v_x}x-\frac{1}{2v_x^2}gx^2,

where H is the initial height of the ball and v_{oy} and v_x the inital velocities in the vertical and horizontal direction, respectively; we have

H=y-\frac{v_{0y}}{v_x}x+\frac{1}{2v_x^2}gx^2.

In this case, the ball landed at the coordinates \left(x,y\right)=\left(61,0\right), so

H=0-\frac{17\sin\left(43\deg\right)}{17\cos\left(43\deg\right)}\times 61+\frac{1}{2\left(17\cos\left(43\deg\right)\right)^2}\times 9.81\times 61^2 \approx 61.19.

8 0
3 years ago
A bus with a vertical wind shield moves horizontally
Katena32 [7]

Answer:

(3) 53°

Explanation:

We want to measure the angle that the rains form with the vertical wind shield, so we have to measure the angle relative to the vertical. This means that we can write the following equation

tan \theta = \frac{v_x}{v_y}

where

v_y = 30 km/h is the speed of the rain, which travels vertically

v_x = 40 km/h is the speed of the bus, which travels horizontally

Substituting, we find

\theta=tan^{-1}(\frac{40}{30})=53^{\circ}

8 0
3 years ago
A ray of light incident in air strikes a rectangular glass block of refractive index 1.50, at an angle of incidence of 45°. Calc
balandron [24]

Answer:

Approximately 28^{\circ}.

Explanation:

The refractive index of the air n_{\text{air}} is approximately 1.00.

Let n_\text{glass} denote the refractive index of the glass block, and let \theta _{\text{glass}} denote the angle of refraction in the glass. Let \theta_\text{air} denote the angle at which the light enters the glass block from the air.

By Snell's Law:

n_{\text{glass}} \, \sin(\theta_{\text{glass}}) = n_{\text{air}} \, \sin(\theta_{\text{air}}).

Rearrange the Snell's Law equation to obtain:

\begin{aligned} \sin(\theta_{\text{glass}}) &= \frac{n_{\text{air}} \, \sin(\theta_{\text{air}})}{n_{\text{glass}}} \\ &= \frac{(1.00)\, (\sin(45^{\circ}))}{1.50} \\ &\approx 0.471\end{aligned}.

Hence:

\begin{aligned} \theta_{\text{glass}} &= \arcsin (0.471) \approx 28^{\circ}\end{aligned}.

In other words, the angle of refraction in the glass would be approximately 28^{\circ}.

7 0
2 years ago
What happens when a roller coaster car moves down from the top of a hill?
VLD [36.1K]
When the roller coaster moves down from the top of the hill, all of its stored potential energy is converted into kinetic energy to move it and when it goes back up the hill it turns kinetic into potential.

3 0
3 years ago
Read 2 more answers
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