<span>Your answer is highland</span>
Answer:
The rotational kinetic energy of the hoop and the instantaneous change rate of the kinetic energy are 2.25 J and 15 J.
Explanation:
Given that,
Mass = 2 kg
Radius = 0.5 m
Angular speed = 3 rad/s
Force = 10 N
(I). We need to calculate the rotational kinetic energy
Using formula of kinetic energy
(II). We need to calculate the instantaneous change rate of the kinetic energy
Using formula of kinetic energy
On differentiating
....(I)
Using newton's second law
Put the value of a in equation (I)
Hence, The rotational kinetic energy of the hoop and the instantaneous change rate of the kinetic energy are 2.25 J and 15 J.
Answer:
Explanation:
Decomposers is the correct answer
Answer:
Length (L2) = 0.51m
Wavelength of string (∆) = 1.02m
Wavelength of sound produced = 0.7795m
Explanation:
Using the equation L1F1 = L2F2
L1 = 0.68m, F1 = 330Hz, F2 = 440Hz
Therefore, (0.68m)(330Hz) = (L2)(440Hz)
L2 = 0.68m × 330hz/440hz
L2 = 0.51m
0.68m - 0.51m = 0.17m from the but
B. ∆ = 2×length (L2)
∆ = 2(0.51) = 1.02m
C. Frequency (f) = 440Hz
V = ∆f
343m/s =∆×440hz
∆ = 343m/s/440hz
∆ = 0.7795m
Answer:
Explanation:
Given the mass of the crate = 10kg
initial speed of the crate = 1.50m/s
pulling force F = 100N
angle of inclination = 20°
Coefficient of kinetic friction = 0.400
Distance traveled by the crate d = 5.00m
Application of newton's second law perpendicular to the inclined plane is used and the detailed calculation is as shown in the attached file.