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kolezko [41]
3 years ago
9

A 92-kg astronaut and a 2000-kg satellite are at rest relative to a space station. the astronaut pushes on the satellite, giving

it a speed of 0.14 m/s directly away from the station. seven and a half seconds later the astronaut comes into contact with the station. part a what was the initial distance from the station to the astronaut?
Physics
2 answers:
just olya [345]3 years ago
8 0
Momentum is conserved. 

<span>Momentum of the satellite is 1600*0.14=224 kg-m/sec </span>
<span>Resulting momentum of the astronaut will be equal -- hence </span>
<span>86*v=224 or the velocity of the astronaut is 2.60 m/sec </span>

<span>In 7.5 seconds the astronaut would travel 19.53 meters</span>
jekas [21]3 years ago
7 0

Answer:

22.8 s

Explanation:

First we calculate the change in momentum of the satellite.

ΔP = 2000 kg (0.14 m/s 0 m/s) = 280 kg·m/s

The change in momentum of the satellite is equal to the change in momentum of the astronaut as a result of Newton's Third law. Therefore:

280 kg·m/s = 92kg * v

                 v = 3.04 m/s

d = speed * time = 3.04 m/s * 7.5 s = 22.8 m

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hope I helped! also when doing multiple choice try using process of elimination. helps alot :P
5 0
3 years ago
A 1.50-m cylindrical rod of diameter 0.500 cm is connected to a power supply that maintains a constant potential difference of 1
nydimaria [60]

Answer:

a) 1.06*10^-5

b) 0.00105 °C^-1

Explanation:

Given that

Length of the cylinder, L = 1.5 m

Radius of the cylinder, r = 0.25 cm

Voltage across the rod, V = 15 V

I• at Temperature T• = 20° C is 18.5 A

I at Temperature T = 90° C is 17.2 A

See attachment for calculations

5 0
3 years ago
Write any three differences between metals and nonmetals​
Alisiya [41]

Metals Non-metals

They are solid at room temperature. They may be solid, liquid and gas at room temperature.

They have high melting and boiling points. They have low melting and boiling points.

They are good conductors of heat and electricity. They are bad conductors of heat and electricity.

4 0
3 years ago
2. The convex mirror shown below has an object placed 15cm in front of it. An image is formed 35 cm
Elena-2011 [213]

Answer:

m = image distance/object distance

m=35/15=7/3

f=uv/(u+v)

35*15/(35+15)

f=10.5cm

4 0
3 years ago
In the Olympic shotput event, an athlete throws the shot with an initial speed of 13.0 m/s at a 47.0° angle from the horizontal.
MariettaO [177]

Answer:

18.7 m

Explanation:

v_{o} = initial speed of the shot = 13 m/s

θ = angle of launch from the horizontal = 47 deg

Consider the motion along the vertical direction

v_{oy} = initial velocity along vertical direction = 13 Sin47 = 9.5 m/s

a_{y} = acceleration along the vertical direction = - 9.8 m/s²

y = vertical displacement = - 1.80 m

t = time of travel

Using the kinematics equation

y=v_{oy} t+(0.5)a_{y} t^{2}

- 1.80 = (9.5) t + (0.5) (- 9.8) t²

t = 2.11 s

Consider the motion along the horizontal direction

x = horizontal displacement of the shot

v_{ox} = initial velocity along horizontal direction = 13 Cos47 = 8.87 m/s

a_{x} = acceleration along the horizontal direction = 0 m/s²

t = time of travel =  2.11 s

Using the kinematics equation

x=v_{ox} t+(0.5)a_{x} t^{2}

x = (8.87) (2.11) + (0.5) (0) (2.11)²

x = 18.7 m

8 0
3 years ago
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