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kobusy [5.1K]
3 years ago
8

An ideal monatomic gas at temperature T is held in a container. If the gas is compressed isothermally, that is at constant tempe

rature, from a volume of Vi to Vf ,
a) What is the change in the (internal) energy of the gas?
b) How much work has been done on the gas?
c) Has heat been transferred into or out of the gas during the process? If so, how much?
d) Show that the 1st law of thermodynamics is satisfied.
Physics
1 answer:
OlgaM077 [116]3 years ago
5 0

Answer:

a) 0 J

b) W = nRTln(Vf/Vi)

c) ΔQ = nRTln(Vf/Vi)

d) ΔQ = W

Explanation:

a) To find the change in the internal energy you use the 1st law of thermodynamics:

\Delta U=\Delta Q-W

Q: heat transfer

W: work done by the gas

The gas is compressed isothermally, then, there is no change in the internal energy and you have

ΔU = 0 J

b) The work is done by the gas, not over the gas.

The work is given by the following formula:

\\W=nRTln(\frac{V_f}{V_i})

n: moles

R: ideal gas constant

T: constant temperature

Vf: final volume

Vi: initial volume

Vf < Vi, then W < 0 and the work is done on the gas

c) The gas has been compressed. Thus, its temperature increases and heat has been transferred to the gas.

The amount of heat is equal to the work done W

d)

\Delta U = \Delta Q-W\\\\0=\Delta Q-W\\\\\Delta Q=W=nRTln(\frac{V_f}{V_i})

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Answer:

KE₂ = 4KE₁

Explanation:

KE₁ = ½mv₁²

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KE₂ = 4(½mv₁²)

KE₂ = 4KE₁

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2 years ago
Let v1, , vk be vectors, and suppose that a point mass of m1, , mk is located at the tip of each vector. The center of mass for
g100num [7]

Answer:

Explanation:

Center of mass is give as

Xcm = (Σmi•xi) / M

Where i= 1,2,3,4.....

M = m1+m2+m3 +....

x is the position of the mass (x, y)

Now,

Given that,

u1 = (−1, 0, 2) (mass 3 kg),

m1 = 3kg and it position x1 = (-1,0,2)

u2 = (2, 1, −3) (mass 1 kg),

m2 = 1kg and it position x2 = (2,1,-3)

u3 = (0, 4, 3) (mass 2 kg),

m3 = 2kg and it position x3 = (0,4,3)

u4 = (5, 2, 0) (mass 5 kg)

m4 = 5kg and it position x4 = (5,2,0)

Now, applying center of mass formula

Xcm = (Σmi•xi) / M

Xcm = (m1•x1+m2•x2+m3•x3+m4•x4) / (m1+m2+m3+m4)

Xcm = [3(-1, 0, 2) +1(2, 1, -3)+2(0, 4, 3)+ 5(5, 2, 0)]/(3 + 1 + 2 + 5)

Xcm = [(-3, 0, 6)+(2, 1, -3)+(0, 8, 6)+(25, 10, 0)] / 11

Xcm = (-3+2+0+25, 0+1+8+10, 6-3+6+0) / 11

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The record time for a Tour de France cyclist to ascend the 1100-mm-high Alpe d'Huez is 37.5 minmin. The rider and his bike had a
katen-ka-za [31]

Answer:

1945.6 W

Explanation:

We are given that

Height,h=1100 m

Time,t=37.5 min=37.5\times 60=2250 s

1 min=60 s

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Power,P=700 W

We have to find the his total metabolic power.

Power,=P'=\frac{W}{t}=\frac{mgh}{t}=\frac{65\times 9.8\times 1100}{2250}=311.4 W

Where g=9.8m/s^2

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They stay in place and vibrate.
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Answer:

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Explanation:

<u>Function Modeling </u>

We can express the relations between different variables and magnitudes in mathematics formulas. This allows us to better manipulate the field data and even make predictions and take decisions out of them.

We know Cortez spends a total of 65 minutes of running and swimming. Let's call r the minutes of running and s the minutes of swimming. The first condition implies that

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Or, equivalently

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The energy burnt when running are 15 calories per minute. It means that he burns 15r in r minutes. Similarly, Cortez burns 6s calories when swimming. The total energy he burns is

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Replacing the formula for s, we get

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\boxed{E=9r+390}

That formula gives the total calories Cortez burns in r minutes of running

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