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Alja [10]
3 years ago
7

Two trumpet players are trying to tune their instruments. When they are in tune, they will both be playing the same note and no

beats will be heard. The more experienced player plays a note with a frequency of 520 Hz. When the second musician begins to play, the note sounds lower and they can hear 20 beats in 4.0 s. With what frequency is the second trumpeter playing?
Physics
1 answer:
marusya05 [52]3 years ago
8 0

Answer:

The second trumpeter will be playing at frequency = 515 Hz

Explanation: Given that the note sounds lower and they can hear 20 beats in 4.0 s. 

Beat frequency = 20/4 = 5 Hz

Beat frequency = F2 - F1

5 = 520 - F1

F1 = 520 - 5

F1 = 515 Hz

Since the note sound lower, the second trumpeter will be playing at 515 Hz frequency

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Explanation:

For this exercise the rotational equilibrium equation should be used

          Σ τ = 0

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                 F = 1300 0.6 / 1.5

                 F = 520 N

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