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3 years ago

Which are the products in the equation CH3SH + 4O2 → CO2 + SO2 +2H2O? Check all that apply. CH3SH, O2 ,CO2, SO2, H2O

Physics

2 answers:

VikaD [51]3 years ago

7 0

Answer:

C D E is the answer

Explanation:

Alona [7]3 years ago

7 0

Answer:

c. CO2 d. SO2 e.H2O

Explanation:

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D th

Explanation:

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3 years ago

A fisherman casts his lure at an angle of 33 degrees above the horizontal. The lure reaches a maximum height of 2.3 m. Assuming

larisa86 [58]

Answer:

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Explanation:

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3 years ago

Peg P is driven by the forked link OA along the path described by r = eu, where r is in meters. When u = p4 rad, the link has an

8_murik_8 [283]

Answer:

The transverse component of acceleration is 26.32 $m/s^2$ where as radial the component of acceleration is 8.77 $m/s^2$

Explanation:

As per the given data

u=π/4 rad

ω=u'=2 rad/s

α=u''=4 rad/s

$r=e^u$

So the transverse component of acceleration are given as

$a_{\theta}=(ru''+2r'u')\\$

Here

$r=e^u\\r=e^{\pi/4}\\r=2.1932 m$

$r'=e^u.u'\\r'=2.1932 \times 2\\r'=4.3864 m$

$a_{\theta}=(ru''+2r'u')\\a_{\theta}=(2.1932\times 4+2\times 4.3864 \times 2)\\a_{\theta}=26.32 m/s\\$

The transverse component of acceleration is 26.32 $m/s^2$

The radial component is given as

$a_r=r''-r\theta'^2$

Here

$r''=e^u.u'^2+e^u u''\\r''=2.1932 \times (2)^2+2.1932\times 4\\r''=17.5456 m$

$a_r=r''-ru'^2\\a_r=17.5456-2.1932\times (2)^2\\a_r=8.7728 m/s^2$

The radial component of acceleration is 8.77 $m/s^2$

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3 years ago

A car has an initial velocity of 20m/s and an average velocity of 30m/s.

Luba_88 [7]

Answer:

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Explanation:

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2 years ago

How much weight can a man lift in the jupiter if he can lift 100kg on the earth.calculate

Nuetrik [128]

Answer:

<h3>2479 Newton</h3>

Solution,

Mass=100 kg

Acceleration due to gravity(g)=24.79 m/s^2

Now,.

 $weight = m \times g \\ \: \: \: \: \: \: \: \: \: \: = 100 \times 24.79 \\ \: \: \: \: \: \: = 2479 \: newton$ 

hope this helps ..

Good luck on your assignment..

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3 years ago