Answer: 3. F1 = F2
Explanation:
According to <u>Newton's law of Gravitation</u>, the force
exerted <u>between two bodies</u> or objects of masses
and
and separated by a distance
is equal to the product of their masses divided by the square of the distance:
(1)
Where
is the gravitational constant
Now, in the especific case of the Earth and the satellite, where the Earth has a mass
and satellite a mass
, being both separated a distance
, the force exerted by the Earth on the satellite is:
(2)
And the force exerted by the satellite on the Earth is:
(3)
As we can see equations (2) and (3) are equal, hence the magnitude of the gravitational force is the same for both:

Explanation:
<em>Given </em>
<em>wavelength </em><em>=</em><em> </em><em>4</em><em> </em><em>m</em>
<em>speed </em><em> </em><em>=</em><em> </em><em>3</em><em>3</em><em>2</em><em> </em><em>m/</em><em>s</em>
<em>frequency </em><em>=</em><em> </em><em>?</em>
<em>We </em><em>know </em><em>we </em><em>have </em><em>the </em><em>formula </em>
<em>wavelength</em><em> </em><em>=</em><em> </em><em>speed </em><em>/</em><em> </em><em>frequency </em>
<em>4</em><em> </em><em>=</em><em> </em><em>3</em><em>3</em><em>2</em><em> </em><em>/</em><em> </em><em>frequency </em>
<em>frequency </em><em>=</em><em> </em><em>3</em><em>3</em><em>2</em><em>/</em><em>4</em>
<em>Therefore </em><em> </em><em>frequency </em><em>is </em><em>8</em><em>3</em><em> </em><em>Hertz </em><em>.</em>
Removing an electron from a neutral atom will result in an atom that is positive.
Answer:
82.1 km
Explanation:
We need to resolve each displacement along two perpendicular directions: the east-west direction (let's label it with x) and the north-south direction (y). Resolving each vector:

Vector B is 48 km south, so:

Finally, vector C:

Now we add the components along each direction:

So, the resultant (which is the distance in a straight line between the starting point and the final point of the motion) is

Amplitude is a measurement of the magnitude of displacement (or maximum disturbance) of a medium from its resting state, as diagramed in the peak deviation example below (it can also be a measurement of an electrical signal's increased or decreased strength above or below a nominal state).