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nadya68 [22]
3 years ago
12

Ah electron is a negatively charged particle that has a charge of magnitude, e - 1.60 x 10-19 C. Which one of the following stat

ements best describes the electric field at a distance r from the electron? The electric field is directed away from the electron and has a magnitude of ke/r. The electric field is directed toward the electron and has a magnitude of ke/r. The electric field is directed toward the electron and has a magnitude of ke/12 The electric field is directed away from the electron and has a magnitude of ke/2 The electric field is directed toward the electron and has a magnitude of ke? /r.
Physics
1 answer:
Advocard [28]3 years ago
5 0

Answer:

The correct statement is "The electric field is directed toward the electron and has a magnitude of \rm \dfrac{ke}{r^2} ".

Explanation:

According to Coulomb's law, the magnitude of the electric field due to a static point charge q at a point r distance away from it is given by

\rm E = \dfrac{k|q|}{r^2}.

  • k is the Coulmob's constant.

The direction of the electric field along the line joining the charge and the point where electric field is to be found and it is directed from positive charge to negative charge.

Conventionally, we assume a positive test charge placed at the point where electric field is to be found, the test charge has very small charge such that its charge does not affect the electric field due to the given charge.

The charge on the electron = -e.

The electric field due to an electron is given by

\rm E = \dfrac{k|-e|}{r^2}=\dfrac{ke}{r^2}.

The direction of this electric field is from positive test charge, placed at the point where electric field is to be found, towards the electron along the line joining the two.

Thus, the correct statement is "The electric field is directed toward the electron and has a magnitude of \rm \dfrac{ke}{r^2} ".

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Answer:

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Explanation:

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When n=1 means it is the closest to the nucleus and is the smallest orbital and with increase in principal quantum number, it depicts that size of the orbital is increasing.

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