Answer:
The rolling basketball has greater momentum.
Explanation:
The momentum of an object is defined as the product of mass and velocity.
Given that the bowling mass has a greater mass than the basketball,
The bowling ball is at rest, so the velocity if the ball is zero.
The basketball is rolling, it has some velocity associated with it.
Therefore, the momentum of the bowling ball is zero.
The basketball has some momentum associated with it.
Hence, the rolling basketball has greater momentum.
Answer:
I am 98% sure that the answers are B and A
Explanation:
Well, actually a heat engine using the Carnot cycle whose cold reservoir is maintained at 0 K could in principle be 100% efficient, even if the hot reservoir was merely at the ambient temperature. Since it costs no energy at all to maintain a heat reservoir at the ambient temperature as long as you have a perfect thermal connection to a large thermal capacitor like your swimming pool or a nearby aquifer you’d have built a perpetual motion machine.
Position of paul with respect to john is given as
14 m due west of john

position of George with respect to Paul is given as 36 m in direction 37 degree south of east

now we need to find the position of George with respect to John
![r_{GJ} = r_G - r_j[\tex]now for the above equation we can add the two equations[tex]r_{Gj} = -14\hat i + 36 cos37\hat i - 36sin37\hat j](https://tex.z-dn.net/?f=r_%7BGJ%7D%20%3D%20r_G%20-%20r_j%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3Enow%20for%20the%20above%20equation%20we%20can%20add%20the%20two%20equations%3C%2Fp%3E%3Cp%3E%5Btex%5Dr_%7BGj%7D%20%3D%20-14%5Chat%20i%20%2B%2036%20cos37%5Chat%20i%20-%2036sin37%5Chat%20j)

so the magnitude is given as

and direction is given as

<em>so it is 26.2 m at an angle 55.75 degree South of east</em>
Answer:
The speed of the particle is 2.86 m/s
Explanation:
Given;
radius of the circular path, r = 2.0 m
tangential acceleration,
= 4.4 m/s²
total magnitude of the acceleration, a = 6.0 m/s²
Total acceleration is the vector sum of tangential acceleration and radial acceleration

where;
is the radial acceleration

The radial acceleration relates to speed of particle in the following equations;

where;
v is the speed of the particle

Therefore, the speed of the particle is 2.86 m/s