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Svetlanka [38]
3 years ago
15

Two objects, labeled A and B, are the same size. Object A has a density of 1.21 g/cm3. Object B has a density of 1.37 g/cm3. Bot

h are placed in a beaker of water. Which will float higher in the water?
Physics
2 answers:
Sedaia [141]3 years ago
4 0

Neither object will float in water. 

They both have densities greater than 1.0 g/cm³,
so both will sink to the bottom of the beaker.

Like rocks.

deff fn [24]3 years ago
4 0

Answer:

None of the object float in water

Explanation:

When an object float in water than we can say that buoyancy force due to water will counter balance the weight of the object

As we can say that

W_g = F_b

so here if object is just floating or we can say that if object is in the state of sinking then we have

\rho_{object} V g = \rho_{water} Vg

so we have

\rho_{object} = \rho_{water}

so from above relation we can say that

i)\rho_{object} > \rho_{water} then it will sink inside water

ii)\rho_{object} < \rho_{water} then it will float in water

since we know density of water is 1 gm/cm^3 so here given both objects are having density more than this

so both the objects will sink inside water

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Aloiza [94]

Answer:

lines of longitude

Explanation:

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2 years ago
A 1.50-m cylindrical rod of diameter 0.500 cm is connected to a power supply that maintains a constant potential difference of 1
nydimaria [60]

Answer:

a) 1.06*10^-5

b) 0.00105 °C^-1

Explanation:

Given that

Length of the cylinder, L = 1.5 m

Radius of the cylinder, r = 0.25 cm

Voltage across the rod, V = 15 V

I• at Temperature T• = 20° C is 18.5 A

I at Temperature T = 90° C is 17.2 A

See attachment for calculations

5 0
3 years ago
A 20 liter cylinder of helium at a pressure of 150 atm and a temperature of 27ÁC is used to fill a balloon at 1.00 atm and 37ÁC.
djyliett [7]

<u>Answer</u>

D) 3100 Liters


<u>Explanation</u>

To get the volume if the balloon you need to use the combined equation of the low of gases.

P₁V₁/T₁ = P₂V₂/T₂

(20×150)/(27+273) = (1×V₂)/(37+273)

3000/300 = V₂/310

10 = V₂/310

V₂ = 10 × 310

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7 0
3 years ago
Read 2 more answers
All household circuits are wired in parallel. A 1140-W toaster, a 270-W blender, and a 80-W lamp are plugged into the same outle
VARVARA [1.3K]

Answer:

total current = 12.417 A

so it will not fuse as current is less than 15 A

Explanation:

given data

toaster = 1140-W

blender = 270-W

lamp = 80-W

voltage = 120 V

solution

we know that current is express as

current = power ÷ voltage   ......................1

here voltage is same in all three device

so

current by toaster is

I = \frac{1140}{120}

I = 9.5 A

and

current by blender

I = \frac{270}{120}

I = 2.25 A

and

current by lamp is

I = \frac{80}{120}

I = 0.667 A

so here device in parallel so

total current is = 9.5 A + 2.25 A + 0.667 A

total current = 12.417 A

so it will not fuse as current is less than 15 A

8 0
2 years ago
a radio station broadcast a frequency 90500 Hz. these radio waves travel at speed of 30000 m/s. what is the wavelength of the ra
Feliz [49]

Answer:

0.331m

Explanation:

wave equation: v=f λ

v=30000m/s

f=90500 Hz

λ= \frac{v}{f}

λ= \frac{30000}{90500}

λ= 0.311m

5 0
2 years ago
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