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Rudik [331]
3 years ago
12

Just as optical astronomers observe the visible light emitted by objects such as stars and galaxies, radio astronomers can also

observe the radio waves emitted by these objects, as well as the radio waves emitted by gas and dust. However, radio telescopes are different from optical telescopes in important ways. In general, compared to optical telescopes, radio telescopes are larger. more curved. more expensive. smaller. This is because
Physics
1 answer:
andre [41]3 years ago
4 0

Answer:

Radio telescopes are LARGER than optical telescopes and this is because radio wavelengths  are much longer than optical wavelengths

Explanation:

In general radio telescopes are LARGER than optical telescopes and this is because radio wavelengths  are much longer than optical wavelengths.

The main difference between radio telescopes and other telescopes especially optical telescopes is based on size and wavelength of both telescopes  

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A wave has a period of 2 seconds and a wavelength of 4 meters. Calculate its frequency and speed. Note: Recall that the frequenc
Angelina_Jolie [31]

Answer:

frequency = 0.5 Hz and speed = 2 m/s

Explanation:

Given that,

The period of a wave, T = 2 s

Wavelength, \lambda=4\ m

If f be the frequency. So,

f = 1/T

f=\dfrac{1}{2}\\\\f=0.5\ Hz

Speed of a wave is given by :

v=f\lambda\\\\v=0.5\times 4\\\\v=2\ m/s

So, the frequency of the wave is 0.5 Hz and speed is 2 m/s.

4 0
3 years ago
A large lightning bolt is observed to have a 19500 A current and move 36 C of charge. What was its duration?
Lynna [10]

Answer:

Its duration is 1.85*10⁻³ s or 1.85 ms

Explanation:

The intensity of electric current I is defined as the amount of electric charge Q (measured in Coulombs) that passes through a section of a conductor in each unit of time. The letter I is used to name the Intensity and its unit is the Ampere (A).

The intensity of electric current is expressed as:

I=\frac{Q}{t}

where:

I: Intensity expressed in Amps (A)

Q: Electric charge expressed in Coulombs (C)

t: Time expressed in seconds (s)

Being:

  • I= 19500 A
  • Q=36 C
  • t=?

Replacing:

19500 A=\frac{36 C}{t}

Solving:

19500 A*t= 36 C

t=\frac{36 C}{19500 A}

t= 1.85*10⁻³ s= 1.85 ms (being 1 s= 1,000 ms)

<u><em>Its duration is 1.85*10⁻³ s or 1.85 ms</em></u>

8 0
3 years ago
Which of the following accurately describes between distance and displacement
klasskru [66]

Distance is a scalar and displacement is a vector

Explanation:

Distance and displacement are two different quantities. Let's review them in detail:

  • Distance is a scalar quantity (only a number followed by unit). Distance represents the total length of the path covered by an object during its motion. Therefore, it does not take into account the direction of motion, in its calculation.
  • Displacement is a vector quantity, so it has a magnitude, a unit and a direction. Displacement is a vector connecting the initial position to the final position of the motion of an object. Therefore, in its calculation, the direction of motion must be taken into account.

Let's see an example in order to understand distance and displacement better.

Imagine a person moving 5 meters forward and then 2 meters backward. In this case:

  • The distance covered by the man is just the total lenght of the path covered, therefore: 5 + 2 = 7 meters
  • The displacement of the man is the distance between the initial and final position. Since the man moved 5 m forward and 2 m backward, his final position is 3 meters forward, therefore the displacement is 3 m in the forward direction.

Learn more about distance and displacement:

brainly.com/question/3969582

#LearnwithBrainly

5 0
4 years ago
A football is kicked into the air from an initial height of 4 feet. The height, in feet, of the football above the ground is giv
kakasveta [241]

Answer: 0.5 seconds or 2.625 seconds

Explanation:

At t = 0, The ball is 4 ft above the ground.

The height of the football varies with time in the following way:

s(t) = -16 t² + 50 t + 4

we need to find the time in which the height would of the football would be 25 ft:

⇒25 = -16 t² + 50 t + 4

we need to solve the quadratic equation:

⇒ 16 t² - 50 t + 21 = 0

t = \frac{50 \pm \sqrt{50^2-4\times 16\times 21}}{2\times16}

⇒ t = 0.5 s or 2.625 s

Therefore, at t = 0.5 s or 2.625 s, the football would be 25 ft above the ground.

3 0
3 years ago
Read 2 more answers
Suppose a box is being dragged by a force of 100 n over a rough surface. if the coefficient of kinetic friction at the interface
Alenkinab [10]
I'm sorry if this is wrong but I think it's 2.5 net
4 0
3 years ago
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