Answer:
frequency = 0.5 Hz and speed = 2 m/s
Explanation:
Given that,
The period of a wave, T = 2 s
Wavelength, 
If f be the frequency. So,
f = 1/T

Speed of a wave is given by :

So, the frequency of the wave is 0.5 Hz and speed is 2 m/s.
Answer:
Its duration is 1.85*10⁻³ s or 1.85 ms
Explanation:
The intensity of electric current I is defined as the amount of electric charge Q (measured in Coulombs) that passes through a section of a conductor in each unit of time. The letter I is used to name the Intensity and its unit is the Ampere (A).
The intensity of electric current is expressed as:

where:
I: Intensity expressed in Amps (A)
Q: Electric charge expressed in Coulombs (C)
t: Time expressed in seconds (s)
Being:
Replacing:

Solving:
19500 A*t= 36 C

t= 1.85*10⁻³ s= 1.85 ms (being 1 s= 1,000 ms)
<u><em>Its duration is 1.85*10⁻³ s or 1.85 ms</em></u>
Distance is a scalar and displacement is a vector
Explanation:
Distance and displacement are two different quantities. Let's review them in detail:
- Distance is a scalar quantity (only a number followed by unit). Distance represents the total length of the path covered by an object during its motion. Therefore, it does not take into account the direction of motion, in its calculation.
- Displacement is a vector quantity, so it has a magnitude, a unit and a direction. Displacement is a vector connecting the initial position to the final position of the motion of an object. Therefore, in its calculation, the direction of motion must be taken into account.
Let's see an example in order to understand distance and displacement better.
Imagine a person moving 5 meters forward and then 2 meters backward. In this case:
- The distance covered by the man is just the total lenght of the path covered, therefore: 5 + 2 = 7 meters
- The displacement of the man is the distance between the initial and final position. Since the man moved 5 m forward and 2 m backward, his final position is 3 meters forward, therefore the displacement is 3 m in the forward direction.
Learn more about distance and displacement:
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Answer: 0.5 seconds or 2.625 seconds
Explanation:
At t = 0, The ball is 4 ft above the ground.
The height of the football varies with time in the following way:
s(t) = -16 t² + 50 t + 4
we need to find the time in which the height would of the football would be 25 ft:
⇒25 = -16 t² + 50 t + 4
we need to solve the quadratic equation:
⇒ 16 t² - 50 t + 21 = 0

⇒ t = 0.5 s or 2.625 s
Therefore, at t = 0.5 s or 2.625 s, the football would be 25 ft above the ground.
I'm sorry if this is wrong but I think it's 2.5 net