We have that the the molarity of methanol in the solution is mathematically given as
Morality=7.91mol/l
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Chemical Reaction</h3>
Question Parameters:
An <u>aqueous </u><em>solution </em>of methanol (MM = 32.04 g/mol)
A molality of 8.83 m and a density of 1.15 g/mL.
Generally the equation for the is mathematically given as

where
Mass of solution=(100+282.2)
Mass of solution=1289.9
Volume=1289.9/1.15
Volume=1.115L
Therefore

Morality=8.83/1.115
Morality=7.91mol/l
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Answer:
43.13Kg of melamine
Explanation:
The problem gives you the mass of urea and two balanced equations:

First we need to calculate the number of moles of urea that are used in the reaction, so:
molar mass of urea = 
The problem says that you have 161.2Kg of urea, so you take that mass of urea and find the moles of urea:
161.2Kg of urea
2684 moles of urea
Now from the stoichiometry you have:
2684 moles of urea
= 447 moles of melamine
The molar mass of the melamine is
so we have:
= 5637.64 g of melamine
Converting that mass of melamine to Kg:
5637.64 g of melamine *
= 56.38 Kg of melamine, that is the theoretical yield of melamine.
Finally we need to calculate the mass of melamine with a yield of 76.5%, so we have:
%yield = 100*(Actual yield of melamine / Theoretical yield of melamine)
Actual yield of melamine =
= 43.13Kg of melamine