During photosynthesis, 5 moles of water are needed to produce 150 grams of glucose. The correct option is D.
<h3>What is photosynthesis?</h3>
It is the process by which green plants and some other organisms use sunlight to synthesize nutrients from carbon dioxide and water.
- Step 1: Write the balanced equation for photosynthesis.
6 CO₂ + 6 H₂O ⇒ C₆H₁₂O₆ + 6 O₂
- Step 2: Convert 150 g of C₆H₁₂O₆ to moles.
The molar mass of C₆H₁₂O₆ is 180.16 g/mol.
150 g × 1 mol/180.16 g = 0.833 mol
- Step 3: Calculate the moles of water required to form 0.833 moles of C₆H₁₂O₆
The molar ratio of H₂O to C₆H₁₂O₆ is 6:1.
0.833 mol C₆H₁₂O₆ × 6 mol H₂O/1 mol C₆H₁₂O₆ = 5.00 mol H₂O
During photosynthesis, 5 moles of water are needed to produce 150 grams of glucose. The correct option is D.
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Answer:
2H₂O₂ → 2H₂O + O₂
24.7 L are the liters of formed oxygen.
Explanation:
We state the reaction:
2H₂O₂ → 2H₂O + O₂
2 moles of peroxide decompose to 2 moles of water and 1 mol of oxygen gas.
We convert the mass to moles: 75 g . 1 mol / 34 g = 2.20 moles
As ratio is 2:1, per 2.20 moles of peroxide I would produce the half of moles, of O₂ → 2.20 /2 = 1.10 moles
We convert the moles to mass → 1.10 mol . 32 g / 1 mol = 35.3 g
Let's use oxygen's density to find out the volume
δ O₂ = 1.429 g/L (mass/volume)
35.3 g . 1L / 1.429g = 24.7 L
Answer:
The energies of combustion (per gram) for hydrogen and methane are as follows: Methane = 82.5 kJ/g; Hydrogen = 162 kJ/g
<em>Note: The question is incomplete. The complete question is given below:</em>
To compare the energies of combustion of these fuels, the following experiment was carried out using a bomb calorimeter with a heat capacity of 11.3 kJ/℃. When a 1.00-g sample of methane gas burned with
<em>excess oxygen in the calorimeter, the temperature increased by 7.3℃. When a 1.00 g sample of hydrogen gas was burned with excess oxygen, the temperature increase was 14.3°C. Compare the energies of combustion (per gram) for hydrogen and methane.</em>
Explanation:
From the equation of the first law of thermodynamics, ΔU = Q + W
Since there is no expansion work in the bomb calorimeter, ΔU = Q
But Q = CΔT
where C is heat capacity of the bomb calorimeter = 11.3
kJ/ºC; ΔT = temperature change
For combustion of methane gas:
Q per gram = (
11.3
kJ/ºC * 7.3°C)/1.0g
Q = 83 kJ/g
For combustion of hydrogen gas:
Q per gram = (
11.3
kJ/ºC * 14.3°C)/1.0g
Q = 162 kJ/g
Answer:
C. the substance in which the solute dissolves
Explanation:
There are two terms in this... the solute and the solvent. The way I learned how to remember this is with a little pirate analogy: The loot (stolen treasure) always goes in the vent. So, the soLUTE goes in the solVENT.
