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2 years ago

How many electrons are in O2.

Chemistry

1 answer:

Liula [17]2 years ago

6 0

Number of electron in O = 8
So, in O2 it would be: 8 * 2 = 16

So, your final answer is 16

Hope this helps!

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7 f Find the volume in dm3 and in mole of 0.505m of NaoH required to react with 40ml of 0.505m

Anna [14]

The volume of NaOH required is 0.08 dm³

To solve this question, we'll begin by writing the balanced equation for the reaction between H₂SO₄ and NaOH. This is illustrated below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

Mole ratio of the acid, H₂SO₄ $(n_{A}) = 1$

Mole ratio of the base, NaOH $(n_{B}) = 2$

Next, we shall determine the volume of NaOH required to react with H₂SO₄. This can be obtained as follow:

Molarity of the base, NaOH $(M_{B}) = 0.505 M$

Volume of the acid, H₂SO₄ $(V_{A}) = 40 mL$

Molarity of the acid, H₂SO₄ $(M_{A}) = 0.505 M$

<h3>Volume of the base, NaOH $(V_{B})$ =? </h3>

$\frac{M_{A} * V_{A}}{M_{B} * V_{B}} = \frac{n_{A}}{n_{B}}\\\\\frac{0.505 * 40}{0.505 *V_{B}} = \frac{1}{2}\\\\\frac{20.2}{0.505 *V_{B}} = \frac{1}{2}$

Cross multiply

$0.505 * V_{B} = 20.2 * 2\\0.505 * V_{B} = 40.4$

Divide both side by 0.505

$V_{B} = \frac{40.4}{0.505}\\\\V_{B} = 80 mL$

Finally, we shall convert 80 mL to dm³. This can be obtained as follow:

$1000 mL = 1 dm^{3}\\\\Therefore,\\\\80 mL = \frac{80 mL * 1dm^{3}}{1000 mL}\\\\80 mL = 0.08dm^{3}$

Therefore, the volume of NaOH required is 0.08 dm³

Learn more: brainly.com/question/19053582

3 0

2 years ago

What is the meaning of barren in this sentence?

JulsSmile [24]

Having little vegetation

Dry and lifeless

Completely empty

5 0

3 years ago

Read 2 more answers

What is the temperature of a gas that is expanded from 3.75 L at 37 degrees Celsius to 5.6 L?

deff fn [24]

Answer:

190 °C

Step-by-step explanation:

The pressure is constant, so this looks like a case where we can use <em>Charles’ Law</em>:

V₁/T₁ = V₂/T₂ Invert both sides of the equation.

T₁/V₁ = T₂/V₂ Multiply each side by V₂

T₂ = T₁ × V₂/V₁

=====

V₁ = 3.75 L; T₁ = (37 + 273.15) K = 310.15 K

V₂ = 5.6 L; T₂ = ?

=====

T₂ = 310.15 × 5.6/3.75

T₂ = 310.15 × 1.49

T₂ = 463 K

t₂ = 463 – 273.15

t₂ = 190 °C

3 0

3 years ago

how many molecule of carbon dioxide are needed to react with excess iron oxide to produce 11.6 g of iron

lesya692 [45]

Answer:

0.16 moles of Carbon

Explanation:

The balanced reaction equation:

$2Fe_{2}O_{3}$ + $3C$ → $4Fe$ + $3CO_{2}$ ↑

The mole ratio of Carbon to Iron is 3 : 4 (since Fe2O3 is in excess)

i.e 3 moles of C produces 4 moles of Fe.

If 1 mole of Fe - 55.8g of Fe

? moles - 11.6g of Fe

= $\frac{11.6}{55.8}$ = 0.208 moles

But 3 moles of C - 4 moles of Fe

? moles of C - 0.208 moles of Fe

= $\frac{3 *0.208}{4}$ = 0.16 moles of carbon.

I hope this explanation was clear and useful.

5 0

3 years ago

Question 15 of 35

Solnce55 [7]

The statements that describe how the pond turned into the bog is as follows: Large water plants grew in shallow water around the edge of the pond.

Pond is an inland body of standing water, either natural or man-made, that is smaller than a lake.

A bog is an area of decayed vegetation (particularly sphagnum moss) which forms a wet spongy ground too soft for walking.

This means that a pond can become a bog when existing plants in the pond decays until the land becomes soft.

Therefore, the statements that describe how the pond turned into the bog is as follows: Large water plants grew in shallow water around the edge of the pond.

Learn more about ponds and bogs at: brainly.com/question/9715563

#SPJ1

7 0

2 years ago