So
y=ax^2+bx+c
(x,y)
sub the points and solve
(4.28,6.48)
6.48=a(4.28)^2+b(4.28)+c
(12.61,15.04)
15.04=a(12.61)^2+b(12.61)+c
well, for 3 variables, we need equations and therefor 3 points
maybe we are supposed to assume it starts at (0,0)
so then
0=a(0)^2+b(0)+c
0=c
so then
6.48=a(4.28)^2+b(4.28)
15.04=a(12.61)^2+b(12.61)
solve for a by subsitution
first equation, minut a(4.28)^2 from both sides
6.48-a(4.28)^2=b(4.28)
divide both sides by 4.28
(6.48/4.28)-4.28a=b
sub that for b in other equation
15.04=a(12.61)^2+b(12.61)
15.04=a(12.61)^2+((6.48/4.28)-4.28a)(12.61)
expand
15.04 =a(12.61)^2+(81.7128/4.28)-53.9708a
minus (81.7128/4.28) both sides
15.04-(81.7128/4.28)=a(12.61)^2-53.9708a
15.04-(81.7128/4.28)=a((12.61)^2-53.9708)
(15.04-(81.7128/4.28))/(((12.61)^2-53.9708))=a
that's the exact value of a
to find b, subsitute to get
(6.48/4.28)-4.28((15.04-(81.7128/4.28))/(((12.61)^2-53.9708)))=b
if we aprox
a≈-0.038573167896199
b≈1.6791118501845
so then the equation is
y=-0.038573167896199x²+1.6791118501845x
Answer:
The correct option is C 20.1%.
Step-by-step explanation:
The probability distribution chart representing the opinions of employed adult women about government funding for day care is as follows:
Rating (<em>X</em>) Probability (<em>p</em>)
1 0.110
2 0.206
3 0.464
4 0.201
5 0.119
The ratings are defined as follows:
1: too little
2: helpful but not enough
3: make a difference but insufficient
4: sufficient
5: generous
The probability of women who think that the support is sufficient is, 0.201.
The percentage is: 0.201 × 100 = 20.1%
Thus, the percentage of women who think that the support is sufficient is 20.1%.
The correct option is C.
Answer: x = 4; x = 5
Step-by-step explanation:
The directions specify to solve by factoring
x^2 - 9x + 20 = 0
To factor, find two numbers that add to -9 and multiply to 20
-5 and -4 work
-5 + (-4) = -9
-5 * -4 = 20
(x - 4)(x - 5) = 0
x = 4, x =5
Answer:
13+37=50
Step-by-step explanation:
C because it has the x variables in the numerator. This is wrong because the x axis represents horizontal movement and slope is rise over run, not run over rise
