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garri49 [273]
3 years ago
8

You are driving in rainy weather, on a highway with bushes and trees along the sides of the road. If you are driving too fast an

d your vehicle goes off the road, you should
Physics
2 answers:
maxonik [38]3 years ago
7 0

Answer:

Personally I would pull over and wait the rain out in my car, preferably parked under a tree.

GuDViN [60]3 years ago
7 0

Answer:

when you are driving on the road in rainy weather on a highway with bushes and trees on both the sides and you are moving on the road with high speed and your vehicle goes off the road what you should is, first of all, apply the brake and park on the side of the road and wait for the weather to clear or drive on the road slowly so that vehicle can make better contact with the road  and vehicle don't slip again.

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If a planet has the same mass as the earth, but has twice the radius, how does the surface gravity, g, compare to g on the surfa
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Answer:

The surface gravity g of the planet is 1/4 of the surface gravity on earth.

Explanation:

Surface gravity is given by the following formula:

g=G\frac{m}{r^{2}}

So the gravity of both the earth and the planet is written in terms of their own radius, so we get:

g_{E}=G\frac{m}{r_{E}^{2}}

g_{P}=G\frac{m}{r_{P}^{2}}

The problem tells us the radius of the planet is twice that of the radius on earth, so:

r_{P}=2r_{E}

If we substituted that into the gravity of the planet equation we would end up with the following formula:

g_{P}=G\frac{m}{(2r_{E})^{2}}

Which yields:

g_{P}=G\frac{m}{4r_{E}^{2}}

So we can now compare the two gravities:

\frac{g_{P}}{g_{E}}=\frac{G\frac{m}{4r_{E}^{2}}}{G\frac{m}{r_{E}^{2}}}

When simplifying the ratio we end up with:

\frac{g_{P}}{g_{E}}=\frac{1}{4}

So the gravity acceleration on the surface of the planet is 1/4 of that on the surface of Earth.

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Answer:

The Answer is (B)

Explanation:

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