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garri49 [273]
3 years ago
8

You are driving in rainy weather, on a highway with bushes and trees along the sides of the road. If you are driving too fast an

d your vehicle goes off the road, you should
Physics
2 answers:
maxonik [38]3 years ago
7 0

Answer:

Personally I would pull over and wait the rain out in my car, preferably parked under a tree.

GuDViN [60]3 years ago
7 0

Answer:

when you are driving on the road in rainy weather on a highway with bushes and trees on both the sides and you are moving on the road with high speed and your vehicle goes off the road what you should is, first of all, apply the brake and park on the side of the road and wait for the weather to clear or drive on the road slowly so that vehicle can make better contact with the road  and vehicle don't slip again.

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Newton's 2nd law describes the relation between
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It describes the relationship between force and acceleration
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What is the frequency of a sound wave commonly called?
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Just remember it as pitch.


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3 years ago
If earth's axis was tilted 45 degrees at what latitudes
givi [52]
23.5 DEGREES is the answer. 
7 0
3 years ago
An 100 kg object traveling at 50 m/s collides (perfectly inelastic) with a 50 kg object initially at rest.
qaws [65]

Answer:

Option C. 5,000 kg m/s

Explanation:

<u>Linear Momentum on a System of Particles </u>

Is defined as the sum of the momenta of each particles in a determined moment. The individual momentum is the product of the mass of the particle by its speed

P=mv

The question refers to an 100 kg object traveling at 50 m/s who collides with another object of 50 kg object initially at rest. We compute the moments of each object

m_1=(100\ kg)(50\ m/s)=5,000\ kg\ m/s

m_2=(50\ kg)(0\ m/s) = 0

The sum of the momenta of both objects prior to the collision is

P=5,000\ kg\ m/s+0\ kg\ m/s

\boxed{ P=5,000\ kg\ m/s}

7 0
3 years ago
The x component of vector is -27.3 m and the y component is +43.6 m. (a) What is the magnitude of ? (b) What is the angle betwee
lara [203]

Answer:51.44 units

Explanation:

Given

x component of vector is -27.3\hat{i}

y component of vector is 43.6\hat{j}

so position vector is

r=-27.3\hat{i}+43.6\hat{j}

Magnitude of vector is

|r|=\sqrt{27.3^2+43.6^2}

|r|=\sqrt{2646.25}

|r|=51.44 units

Direction

tan\theta =\frac{43.6}{-27.3}=-1.597

vector is in 2nd quadrant thus

180-\theta =57.94

\theta =122.06^{\circ}

4 0
3 years ago
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