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oksian1 [2.3K]
3 years ago
10

Mary pushes a crate by applying force of 18 newtons. Unable to push it alone, she gets help from her friend, Anne. Together they

apply a force of 43 newtons, and the crate just starts moving. If the coefficient of static friction is 0.11, what is the value of the normal force?
Physics
2 answers:
nekit [7.7K]3 years ago
7 0

Answer:

The answer is C

Explanation:

defon3 years ago
4 0
This problem is relatively simple, in order to solve this problem the only formula you need to know is the formula for friction, which is: 

<span>Ff = UsN </span>

<span>where Us is the coefficient of static friction and N is the normal force. </span>

<span>In order to get the crate moving you must first apply enough force to overcome the static friction: </span>

<span>Fapplied = Ff </span>

<span>Since Fapplied = 43 Newtons: </span>

<span>Fapplied = Ff = 43 = UsN </span>

<span>and it was given that Us = 0.11, so all you have to do is isolate N by dividing both sides by 0.11 </span>

<span>43/0.11 = N = 390.9 which is approximately 391 or C. 3.9x10^2</span>
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