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3 years ago

26. A solid wheel accelerates at 3.25 rad/s2 when a

Physics

1 answer:

Yanka [14]3 years ago

5 0

Answer:

9.0 N

Explanation:

The location of the mass of the wheel on the wheel = Evenly distributed

The acceleration of the solid wheel, α = 3.25 rad/s²

The applied force on the wheel = 4.5 N

The location mass of the replacement wheel = All on (around) the rim

The moment of inertia of the new wheel, I = m·r² (From an online source)

We have;

The moment of inertia for a solid wheel = 1/2·m·r²

The torque, τ = Moment of inertia, I × Acceleration, α

For the solid wheel, we have;

τ = 1/2·m·r² × 3.25 rad/s²

τ = r × F = r × m × a

For the replacement wheel, we have;

τ = m·r² × 3.25 rad/s² = 2 × 1/2·m·r² × 3.25 rad/s²

∴ τ = 2 × r × F

Given that the radius remains the same, the force applied on the replacement wheel needs to be doubled

The force that should be exerted on the strap to give the same angular velocity, F' = 2 × F

The required force, F' = 2 × 4.5 N = 9.0 N.

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A jeep starts from rest with a constant acceleration of 4m/s2.At the same time a car travels with a constant speed of 36km/h ove

Phantasy [73]

Answer:

25m

Explanation:

Let's assume the Jeep attains a velocity of 36km/h ; a constant speed same with that of the car.

While the Jeep is accelerating to that speed, the car with that speed passes it.

Now we can calculate the time taken for the Jeep to attain the velocity of 36km/h on her constant acceleration.

This time is t = v/a; from Newton's Law of Motion:

a = V-U / t ; a-acceleration

V is final velocity = 36km/h

U is initial velocity 0 since the body starts from rest.

Hence t = 36000/3600 ÷ 4 = 2.5s

Note conversting from km/h to m/s we multiply by 1000/3600.

But the distance covered by the car while the Jeep just accelerates is

S = U × t = 10× 2.5 = 25m.

Note From Newton's law of Motion, distance for constant speed is defined as: U × t

Hence the Car would be 25m off the starting point just as the Jeep accelerates. It would overtake the Jeep when it just covers 25m from the Jeep starting point.

5 0

3 years ago

brainly an electric heating element is connected to a 110V circuit and a current of 3.2A is flowing through the element. how muc

Naya [18.7K]

Energy used by the element = 6336000 j

The electrical energy is given by

E= V i t

V= voltage= 110 V

i= current=3.2 A

t= time= 5 h= 5 (3600)= 18000 s

so energy= E= 110 (3.2)(18000)

E=6336000 J

3 0

3 years ago

To test a slide at an amusement park, a block of wood with mass 3.00 kgkg is released at the top of the slide and slides down to

dem82 [27]

Answer:

511.1 J

Explanation:

We are given that

Mass of wood block=m=3 kg

Vertical distance,h=23 m

Horizontal distance =x=30 m

Distance traveled in downward direction y=40 m

Initial velocity,u=0

$y=ut+\frac{1}{2} gt^2$

Where $g=9.8 m/s^2$

$40=0+\frac{1}{2}(9.8)t^2=4.9t^2$

$t^2=\frac{40}{4.9}$

$t=\sqrt{\frac{40}{4.9}}=2.86 s$

$x=v_x\times t$

$30=v_x(2.86)$

$v=v_x=\frac{30}{2.86}=10.49 m/s$

By work energy theorem

Change in kinetic energy=Work done= mgh-W

$\frac{1}{2}mv^2-\frac{1}{2}mu^2=3\times 9.8\times 23-W$

$\frac{1}{2}(3)(10.49)^2-0=676.2-W$

$W=676.2-\frac{1}{2}(3)(10.49)^2=511.1 J$

Hence, the work done due to friction on the block as it slides down the ramp=511.1 J

6 0

3 years ago

The following voltage drops are measured across three resistors in series: 5.5 V. 8.2 V. and 12,3 V. What is the value of the so

DiKsa [7]

Answer:

26 V

Explanation:

Given:

The three resistors 5.5 V. 8.2 V. and 12,3 V. are connected in series.

Now we have to find out the source voltage to which these resistors arc connected ?

Solution:

As we know in series the magnitude of current is uniform but the voltage divides between the resistors supplied from source voltage.So the magnitude of source voltage is, 5.5 V + 8.2 V + 12.3 V = 26 V

Hence, the value of the source voltage to which these resistors are connected is 26 V

7 0

4 years ago

Some instruments differentiate individual quanta of electromagnetic radiation based on their energies. assume such an instrument

lesya [120]

There is a relationship between the energy of a photon and its wavelength. This can be expressed as a mathematical equation shown below:

E = hc/λ
where
h is the Planck's constant equal to 6.62607004 × 10⁻³⁴ m²<span> kg / s
c is the speed of light equal to 3</span>× 10⁸ m/s
λ is the wavelength

3.5×10⁻¹⁶ J = (6.62607004 × 10⁻³⁴ m² kg / s)(3× 10⁸ m/s)/λ
Solving for λ,
λ = 56.8×10⁻⁹ m or<em> 56.8 nm</em>

5 0

4 years ago