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3 years ago

The following angles are given in degrees and

Physics

1 answer:

Firdavs [7]3 years ago

4 0

bonjour je dis juste un peu de mots aléatoires si vous répondez par "je veux une pizza" cela signifie que vous comprenez et alors et seulement alors je répondrai à votre question

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Water that flows from behind a large dam can cause machines to produce electricity. What change takes place?

lyudmila [28]

The mechanical energy in the falling water is used to spin the generator, and gets transformed into electrical energy. That's the first choice on the list.

8 0

3 years ago

What does the REVOLUTION of Earth around the Sun bring us and how long does it take?

olasank [31]

Answer:

takes 365 days and it bring us seasons such as, spring,winter and fall.

7 0

3 years ago

Water drips from a shower head (the sprayer at the top of the shower) and falls onto the floor 2.4 m below. The droplets are fal

expeople1 [14]

Answer:

The third drop is 0.26m

Explanation:

The drop 1 impacts at time T is given by:

T=sqrt(2h/g)

T= sqrt[(2×2.4)/9.8]

T= sqrt(4.8/9.8)

T= sqrt(0.4898)

T= 0.70seconds

4th drops starts at dT=0.70/3= 0.23seconds

The interval between the drops is 0.23seconds

Third drop will fall at t= 0.23

h=1/2gt^2

h= 1/2×9.81×(0.23)^2

h= 0.26m

4 0

3 years ago

Help me get a answer

daser333 [38]

Answer:

I think D sorry if I'm wrong

6 0

2 years ago

A 5kg bag falls a verticle height of 10m before hitting the ground.

g100num [7]

Answer:

$u = 7m {s}^{ - 1}$

Explanation:

We know that when we don't have air friction on a free fall the mechanical energy (I will symbololize it with ME) is equal everywhere. So we have:

$me(1) = me(2)$

where me(1) is mechanical energy while on h=10m

and me(2) is mechanical energy while on the ground

Ek(1) + DynamicE(1) = Ek(2) + DynamicE(2)

Ek(1) is equal to zero since an object that has reached its max height has a speed equal to zero.

DynamicE(2) is equal to zero since it's touching the ground

Using that info we have

$m \times g \times h = \frac{1}{2} \times m \times u {}^{2} \\$

we divide both sides of the equation with mass to make the math easier.

$9.8 \times 10 = \frac{1}{2} \times u {}^{2} \\ \frac{98}{2} = u {}^{2} \\ u { }^{2} = 49 \\ u = 7$

7 0

3 years ago