No, the dilution does not change the number of moles dissolved
Explanation:
We can see that,
The molarity of the solution was 0.50 M
The volume of the solution is 10 ml.
No of moles of the solute was= volume * concentration
= 10 X 10^-3* 0.50
= 5*10^-3 moles
When the solution is diluted from 10 ml to 100ml, the molarity or concentration changes but number of moles remains constant.
The molarity of 100 ml solution will be
c=n/V
= 5*10^-3*/100*10^-3
= 0.05
when the solution is diluted to 100ml from 10 ml molarity changes from 0.5M TO 0.05 M
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D) A log of who has handled the evidence and when so the integrity of the evidence is upheld.
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A 0.25m solution of NaCl is defined as a solution consisting of 0.25mol NaCl dissolved in 1kg water:
Which choice fits this definition: None does. I suggest that you recheck the data you have submitted - you have a mixture of moles, mass, etc and it is easy to make a mistake.
d) looks promising if it was: 1.0 mol NaCl dissolved in 4kg water.
I have overlooked C) as possible 0.25mol NaCl in 1kg water as being a little too obvious.
The correct answer for, An element with the smallest anionic (negative-ionic) radius would be found on the periodic table in, is <span>Group 17, Period 2.</span>
