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amm1812
3 years ago
13

How does one recognize a redox reaction?

Chemistry
1 answer:
nika2105 [10]3 years ago
3 0

Answer:

A.

Explanation:

A redox reaction is a reaction when oxidation states (or numbers) change during reaction.

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Calculate the freezing point of a 0.08500 m aqueous solution of nano3. the molal freezing-point-depression constant of water is
Citrus2011 [14]
Depression in freezing point (ΔT_{f}) = K_{f}×m×i,
where, K_{f} = cryoscopic constant = 1.86^{0} C/m,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For NaNO_{3})

Thus, (ΔT_{f}) = 1.86 X 0.0085 X 2 = 0.03162^{0}C

Now, (ΔT_{f}) = T^{0} - T
Here, T = freezing point of solution
T^{0} = freezing point of solvent = 0^{0}C
Thus, T = T^{0} - (ΔT_{f}) = -0.03162^{0}C
8 0
3 years ago
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Which atom attracts electrons more strongly?
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Bromine attracts electrons more strongly. Cesium is In fact the least electro negative element.

Sodium is more likely to lose an electron because is is less electro negative. Strong electronegativity make the element want more electrons. Sodium has loose electrons with a lower electronegativity so it gives it up easier.
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4 years ago
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Wear _______________________ when handling batteries, because they can explode or leak.
Basile [38]

The answer is: b. Safety glasses and acid-resistant gloves.

Battery acid (sulfuric acid) has pH = 0.

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Chemical dissociation of sulfuric acid in water:  

H₂SO₄(aq) → 2H⁺(aq) + SO₄²⁻(aq).  

Sulfuric acid can come in contact with eyes and hands, so it is important to wear safety glasses and acid-resistant gloves.

4 0
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Suppose the data formed a line with a steeper slope. For the same change in temperature, how would the change in volume compare?
bogdanovich [222]
Substances can change state, usually when they are heated or cooled. For example, liquid water turns into steam when it is heated enough, and it turns into ice when it is cooled enough. ... The closeness, arrangement and motion of the particles in a substance change when it changes state.
4 0
2 years ago
At constant pressure, which of these systems do work on the surroundings? A ( s ) + B ( s ) ⟶ C ( g ) A(s)+B(s)⟶C(g) 2 A ( g ) +
Tju [1.3M]

Correct question:

At constant pressure, which of these systems do work on the surroundings?

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

(c) A ( g ) + B ( g ) ⟶ C ( g )

(d) 2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

Answer:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

Explanation:

Work done by a system on the surroundings at a constant pressure is given as;

W = -PΔV

Where;

ΔV is gas expansion, that is final volume of the gas minus initial volume of the gas must be greater than zero.

Part (a)

A ( s ) + B ( s ) ⟶ C ( g )

ΔV = 1 - (0) = 1 (expansion)

Part (b)

2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

ΔV = 5 - ( 2+ 2) = 1 (expansion)

Part (c)

A ( g ) + B ( g ) ⟶ C ( g )

ΔV = 1 - ( 1 + 1) = -1 (compression)

Part (d)

2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

ΔV = 3 - ( 4) = -1 (compression)

Thus, systems where there is gas expansion are in part (a) and part (b). The correct answers are:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

4 0
3 years ago
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