We will use the formula for freezing point depression :
but first, we need to get the molality m of the solution:
- molality m = moles of C2H5OH / mass of water Kg
when moles of C2H5OH = mass of C2H5OH/ molar mass of C2H5OH
= 11.85 g / 46 g/mol
= 0.258 moles
and when we have the mass of water Kg = 0.368 Kg
so, by substitution on the molality formula:
∴ molality m = 0.258 moles / 0.368 Kg
= 0.7 mol/Kg
and when C2H5OH is a weak acid so, there is no dissociation ∴ i = 1
and when Kf is given = 1.86 C/m
so by substitution on ΔTf formula:
when ΔTf = i Kf m
∴ ΔTf = 1 * 1.86C/m * 0.7mol/Kg
= 1.302 °C
Which atoms? ~~~~~~~~~~~~~~~~~~~~~~~~~`
Answer:
Turning the lights off when they're not needed.
Among the elements Barium has the lowest Ionization Energy.
<h3>What is Ionization Process ?</h3>
The process by which any neutral atom gets converted into electrically charged by gaining or losing electron is called Ionization Process.
K is an alkali metal it has to lose one electron to attain stable electronic configuration of an inert gas
For removing second electron , a stable configuration has to be broken and so will require high amount of energy.
Ca and Ba are alkaline earth metals.
They both have to lose 2 electrons to attain stable electronic configuration of noble gas.
They have low Iow Ionization Energy as compared to K.
Ca has higher Ionization Energy as compared to Ba because when we move down the periodic table , The ionization energy decreases.
Hence , Among the elements Barium has the lowest Ionization Energy.
To know more about Ionization Process
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Answer:
Hope this helps
Explanation:
These are called quantum numbers: there are 4, but the first three are mainly used, only in orbital notation will you use all four.
The first is the electron's energy level or "shell", used as n. (Principle QN)
The second relates to the shape of the orbital and is used as l, when n and l are put together it defines the sublevel or subshell. (Angular Momentum QN)
The third one relates to the orientation of the electrons in that sublevel used as m(sub)l. (Magnetic QN)
The fourth one relates to the spin states of the electron, since they spin opposite directions, used as m(sub)s. (Electron Spin QN)