Answer: I think you have to subtract the distances
Explanation:
Answer:
14.32g
Explanation:
Initial temperature = 83.8°C
Final temperature = 77.1°C
Temperature change, ΔT = 83.8°C - 77.1°C = 6.7
Heat, H = 167J
Specific heat, c = 1.740J/g °C
m = ?
All these parameters are related with the equation below;
H = mcΔT
m = H / cΔT
m = 167 / (1.740 * 6.7)
m = 167 / 11.658 = 14.32g
Answer: 1-82 2-7.4 3-355 4-.93
Explanation:
answers on edg
Since there is no sample, let us assume 100 g of the solution:
(22.2% of 100 g) / (46.0254 g HCOOH/mol) = 0.48234 mol HCOOH
(100 g - 22.2 g) = 77.8 g = 0.0778 kg water
(0.48234 mol HCOOH) / (0.0778 kg) = 6.1997 mol/kg = 6.20 m HCOOH
(77.8 g H2O) / (18.01532 g H2O/mol) = 4.3185 mol H2O
(0.48234 mol HCOOH) / (0.48234 mol + 4.3185 mol) = 0.100 [the mole fraction of HCOOH]
