1. The volume of ammonia consumed in the reaction is 23.2 L
2. The volume of oxygen consumed in the reaction is 29 L
<h3>Balanced equation</h3>
4NH₃(g) + 5O₂(g) --> 4NO(g) + 6H₂O(g)
From the balanced equation above,
6 L of H₂O were produced from 4 L of NH₃ and 5 L of O₂
<h3>1. How to determine the volume of ammonia, NH₃ consumed</h3>
From the balanced equation above,
6 L of H₂O were produced from 4 L of NH₃
Therefore,
34.8 L of H₂O will be produced from = (34.8 × 4) / 6 = 23.2 L of NH₃
Thus, 23.2 L of NH₃ were consumed
<h3>2. How to determine the volume of oxygen, O₂ consumed</h3>
From the balanced equation above,
6 L of H₂O were produced from 5 L of O₂
Therefore,
34.8 L of H₂O will be produced from = (34.8 × 5) / 6 = 29 L of O₂
Thus, 29 L of O₂ were consumed
Learn more about stoichiometry:
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