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Jet001 [13]
3 years ago
11

An acid-base titration is a neutralization reaction performed to determine: the concentration of an unknown acid based upon the

concentration of a known base
the concentration of an unknown acid based upon the concentration of a known acid
the amount of salt that will be produced from the reaction of the acid and base the amount of water that will be produced from the reaction of the acid and base
Chemistry
1 answer:
Inga [223]3 years ago
6 0

A is your answer, "the concentration of an unknown acid based upon the concentration of a known base"

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What mass of butane in grams is necessary to produce 1.5×103 kj of heat what mass of co2 is produced?
kari74 [83]
The heat of reaction (i.e. combustion) of butane (C_{4} H_{10}) when reacted with oxygen (O_{2})  is -2658 kJ/mol butane, and the chemical reaction is given by: 

C_{4} H_{10} + \frac{13}{2} O_{2} ---> 4 CO_{2}  + 5 H_{2}O

The mass of butane required in the reaction is based on the heat produced by the reaction, which is given to be -1,500 kJ. The minus sign is added because the reaction releases heat (exothermic), which means that the products are in a "lower energy state" than the reactants. 

Dividing this with the heat of reaction per mole of butane reacted would give the number of moles butane required. Then, multiplying the answer with the molar mass of butane which is 58 grams/mole, will give the mass of butane required. 

Moles of butane = [(-1,500 kJ)/(-2658 kJ/mol butane)]
Moles of butane = 0.5643 moles butane

Mass of butane  = 0.5643 moles butane * 58 grams/mol butane
Mass of butane  = 32.73 grams butane

The mass of carbon dioxide (CO_{2}) can be determined by multiplying the moles of butane (C_{4} H_{10}) with the mole ratio of (CO_{2}) produced to the (C_{4} H_{10}) reacted, and then with the molar mass of (CO_{2}), which is 44 grams/mole. 

Mass of carbon dioxide produced 
    = 0.5643 moles butane * [4 moles CO_{2}/ 1 mole C_{4} H_{10}] * 44 grams/mole CO_{2}

Mass of carbon dioxide produced  
    = 99.32 grams CO_{2}

Thus, the mass of butane required is 32.73 grams, and the mass of carbon dioxide produced from the reaction of this amount of butane is 99.32 grams. 
                
4 0
3 years ago
Read 2 more answers
Which of the following claims may be made based on your observations? (You will recieve negative points for wrong answers.)
Ostrovityanka [42]

Answer:

D, E and F

Explanation:

About tetrachloro cobalt complexes, the following facts have been observed  

  • Color of the tetrachloro cobalt complexes is blue.
  • They do not decompose on heating that means synthesis of tetra chloro is endothermic.

About hexa aqua cobalt complexes, the following facts have been observed  

  • Color of the hexa aqua cobalt complexes is pink color.
  • They decompose on heating and remain stable on cooling that means process of synthesis of hexa aqua cobalt complexes is exothermic.

Based on above, the correct statements are:

The correct is chloro cobalt complex is blue and aqua cobalt  

complex is pink.  

The chloro complex is favored by heating.

If the chloro complex is a product, then the reaction must be endothermic.

The correct options are D, E and F.

8 0
3 years ago
N2-3H2 → 2NH3
aniked [119]

Answer:

6 mols H2 are needed

Explanation:

N2 = 28.01g/mol

H2 = 2.02g/mol

\frac{2 mol N_{2} }{1} * \frac{3 mol H_{2}  }{ 1 mol N_{2} } = 6 mol H2

8 0
3 years ago
Please help me out asap. I’ll give brainliest
mestny [16]

Answer:

I belive the answer is A but the image quality is hard to tell.

Explanation:

As pressure increases the higher the melting point of rock becomes making it harder to melt, thats why molten rocks brought to the surface melt because of the change in pressure.  

7 0
2 years ago
How many moles of carbon are in 25 grams of carbon
Brut [27]

Answer:

One mole of carbon would look like 25/12.01

Explanation:

Firstly, you will divide 25 by 12.01 and get 2.081598  

We know 1 mole equals the gram per atomic mass,  so one mole of carbon is 12.01 grams. In conclusion, it would look like 25/12.01.

4 0
3 years ago
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