All categories

3 years ago

Plans used for work that has to do with construction in or around earth are called

Physics

1 answer:

attashe74 [19]3 years ago

7 0

Plans used for work that has to do with construction in or around Earth are called, “Civil Plans.”

Hope this helped!

You might be interested in

PLZ HELP ITS A TIMED TEST!!!!!!!!!!!!!!!!

sergij07 [2.7K]

Image #3 good luck!!!!!!!!!!!

7 0

3 years ago

The total charge a battery can supply is rated in mA⋅h , the product of the current (in mA ) and the time (in h ) that the batte

natita [175]

Answer: 0.2 hours

Explanation: In order to solve this question we have to considerer that a recargeable battery can supply 1800 mA in one hour then we have to determine how long could this battery drive current through a long, thin wire of resistance 34 Ω .

Besides, this battery has a voltage of 12 V

so by using the Ohm law we also know that V=R*I,

Fron this we can obtain:

I= V/R= 12 V/ 34 Ω=0.35 A= 350 mA

then considering that this battery can supply 1800 mA in one hour we have this battery can supply 350 mA in x time in the form:

1hour------- 1800 mA

x hour--------350 mA

time= 350/1800= 0.2 hour

4 0

3 years ago

[BWS.02]If the same experiment is repeated in different parts of the world by different scientists,

guajiro [1.7K]

Answer:

the results will be the same.it may be

7 0

3 years ago

A vibrating object produces periodic waves with a wavelength of 53 cm and a frequency of 15 Hz. How fast do these waves move awa

DerKrebs [107]

Answer:

v = 7.95 m/s

Explanation:

Given that,

Wavelength of a wave, $\lambda=53\ cm=0.53\ m$

Frequency of a wave, f = 15 Hz

We need to find the speed of the wave. The speed of a wave is given by :

$v=f\lambda\\\\v=15\ Hz\times 0.53\ m\\\\v=7.95\ m/s$

So, the wave move with a speed of 7.95 m/s.

5 0

3 years ago

The maximum wavelength an electromagnetic wave can have and still eject an electron from a copper surface is 264 nm .What is the

Tamiku [17]

Answer:

4.71 eV

Explanation:

For an electromagnetic wave with wavelength

$\lambda=264 nm = 2.64\cdot 10^{-7} m$

the energy of the photons in the wave is given by

$E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2.64\cdot 10^{-7}m}=7.53\cdot 10^{-19} J$

where h is the Planck constant and c the speed of light. Therefore, this is the minimum energy that a photon should have in order to extract a photoelectron from the copper surface.

The work function of a metal is the minimum energy required by the incident light in order to extract photoelectrons from the metal's surface. Therefore, the work function corresponds to the energy we found previously. By converting it into electronvolts, we find:

$E=\frac{7.53\cdot 10^{-19} J}{1.6\cdot 10^{-19} J/eV}=4.71 eV$

3 0

3 years ago