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3 years ago

Explain applications

Physics

1 answer:

hoa [83]2 years ago

3 0

Answer:

See explanation

Explanation:

MRI: Magnetic resonance imaging (MRI) is a modern medical imaging technique that have proven to be invaluable in radiology because it is used to obtain pictures of the anatomy and the physiological processes of the human body. MRI scanners make use of strong magnetic fields and radio waves to obtain images of the target organs of the human body.

X-Ray: X-ray is an electromagnetic wave. It is used in medicine to examine the body in order to locate broken bones and metallic objects like bullets. It is used to detect flaws in metal castings and in airports to detect metals in baggage. It is used to investigate the structure of crystals as well as in cancer treatment.

Ultrasound: In medicine, the applications of ultrasound may be surgical, therapeutic, or diagnostic. Also, It is used to detect defects, flaws, cracks in machine parts, bridges and buildings.

Infrared Radiation : Infrared thermal-imaging cameras can be used to take pictures even in the dark. It is very useful in heat sensing. Lastly, it is used in chemistry to study chemical bonds.

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An 800kg roller coaster starts from top of a 45m hill with a velocity of 4m/s. The car travels to the bottom, through a loop, an

aalyn [17]

Let's start with the total amount of energy available for the whole scenario:
Some kind of machine gave the coaster a bunch of potential energy by
dragging it up to the top of a 45m hill,and that's the energy is has to work with.

Potential energy = (M) (G) (H) = (800) (9.8) (45) = 352,800 joules

It was then given an extra kick ... enough to give it some kinetic energy, and
start it rolling at 4 m/s.

Kinetic energy = (1/2) (M) (V)² = (1/2) (800) (4)² = 6,400 joules

So the coaster starts out with (352,000 + 6,400) = 359,200 joules of energy.

There's no friction, so it'll have that same energy at every point of the story.
=================================

Skip the loop for a moment, because the first question concerns the hill after
the loop. We'll come back to it.

The coaster is traveling 10 m/sat the top of the next hill. Its kinetic energy is

(1/2) (M) (V)² = (400) (10)² = 40,000 joules.

Its potential energy at the top of the hill is (359,200 - 40,000) = 319,200.

PE = (M) (G) (H)

319,200 = (800) (9.8) (H)

H = (319,200) / (800 x 9.8) = 40.71 meters
=================================

Now back to the loop:

You said that the loop is 22m high at the top. The PE up there is

PE = (M) (G) (H) = (800) (9.8) (22) = 172,480 joules

So the rest is now kinetic. KE = (359,200 - 172,480) = 186,720 joules.

KE = (1/2) (M) (V)² = 186,720

(400) (V)² = 186,720

V² = 186,720 / 400 = 466.8

V = √466.8 = 21.61 m/s
===============================

Now it looks like there should be another question ... that's why they
bothered to tell you that the end is 4m off the ground. They must
want you to find the coaster's speed when it gets to the end.

At 4m off the ground, PE = (M) (G) (H) = (800) (9.8) (4) = 31,360 joules.

The rest will be kinetic. KE = (359,200 - 31,360) = 327,840 joules

KE = (1/2) (M) (V)² = 327,840

400 V² = 327,840

V² = 327,840 / 400 = 819.6

V = √819.6 = 28.63 m/s at the end
=======================================

If the official answers in class are a little bit different from these,
it'll be because they used some different number for Gravity.
I used '9.8' for gravity, but very often, they use '10' .

If the official answers in class are way way different from these,
then I made one or more big mistakes somewhere. Sorry.

6 0

2 years ago

A point on a wheel of radius 40 cm that is rotating at a constant 5.0 revolutions per second is located 0.20 m from the axis of

Margarita [4]

Answer:

$197.2 m/s^2$

Explanation:

The centripetal acceleration of a point moving by circular motion is given by:

$a=\omega^2 r$

where

$\omega$ is the angular velocity

r is the distance from the axis of rotation

The point on the wheel makes 5.0 revolutions per second, so the frequency is

$f=\frac{5}{1}=5 Hz$

and the angular velocity is

$\omega=2\pi f = 2\pi (5)=31.4 rad/s$

While the distance of the point from the axis of rotation is

$r=0.20 m$

Substituting, we find the acceleration:

$a=(31.4)^2(0.20)=197.2 m/s^2$

5 0

2 years ago

Read 2 more answers

More friction causes more what? A. Drag B. Weight C. Lift D. Thrust

yaroslaw [1]

Answer:

A. Drag

Explanation:

This is because, since friction tends to oppose the motion of an object, and drag affects an object moving in a fluid, the more the friction, the more the drag on the object.

6 0

2 years ago

When riding a 10-speed bicycle up a hill, a cyclist shifts the chain to a larger-diameter gear attached to the back wheel. Why i

dimaraw [331]

To solve this problem we will use the concepts of the moment of rotational inertia, angular acceleration and the expression of angular velocity.

The rotational inertia is expressed as follows:

$I = \sum mr^2$

Here,

m = Mass of the object

r = Distance from the rotational axis

The rotational acceleration in terms of translational acceleration is

$\alpha = \frac{a}{R}$

Here,

a = Acceleration

R = Radius of the circular path of the object

The expression for the rotational speed of the object is

$\omega = \frac{\Delta \theta}{\Delta t}$

Here,

$\Delta \theta$ is the angular displacement of the object

The explanation by which when climbing a mountain uphill is changed to a larger pinion, is because it produces a greater torque but it is necessary to make more pedaling to be able to travel the same distance. Basically every turn results in less rotations of the rear wheel. Said energy that was previously used to move the rotation of the wheel is now distributed in more turns of the pedal. Therefore option a and c are correct.

This would indicate that the correct option is D.

8 0

3 years ago

A wave has an amplitude of 2 cm. What is its energy (KW)?

omeli [17]

Answer:

1.962 × 10⁻³ kW

Explanation:

The energy of a wave of a wave, such as an ocean wave, in regions of considerable water depth given its amplitude in a meter of crest and surface unit is given by the relation;

$E = \dfrac{\rho \times g \times A^2}{2}$

Where:

ρ = Density of water = 1000 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

A = Wave amplitude = 2 cm = 0.02 m

We therefore have;

$E = \dfrac{1000 \times 9.81 \times (0.02)^2}{2} = 1.962 \ \dfrac{m^2 \cdot kg}{s^2} = 1.962 \ J$

The energy is power is the energy per second which is gives;

P = E /second = 1.962 J/s = 1.962 W = 1.962 × 10⁻³ kW.

4 0

3 years ago