Answer:
The question is incomplete. Here is the complete question:
A Blu-ray disc is approximately 8 centimeters in diameter. The drive motor of the Blu-ray player is able to rotate up to 10,000 revolutions per minute, depending on what track is being read. (a) Find the maximum angular speed (in radians per second) of a Blu-ray disc as it rotates. (b) Find the maximum linear speed (in meters per second) of a point on the outermost track as the disc rotates.
Answer:
(a) 1047.2 rad/sec
(b) 41.9 m/s
Explanation: Please see the attachments below
Answer:
<h2>the car must move with the speed</h2><h2>
</h2>
Explanation:
As we know that the momentum of the car and truck is same
so as per the formula of momentum we have
so we have
so we will have
So the car must move with the speed
Yes the answer is recoiled of the Gaian and the hash of attorney then the distance must be bábale of the original number
Answer:
The width of the slit is 0.4 mm (0.00040 m).
Explanation:
From the Young's interference expression, we have;
(λ ÷ d) = (Δy ÷ D)
where λ is the wavelength of the light, D is the distance of the slit to the screen, d is the width of slit and Δy is the fringe separation.
Thus,
d = (Dλ) ÷ Δy
D = 3.30 m, Δy = 4.7 mm (0.0047 m) and λ = 563 nm (563 ×
m)
d = (3.30 × 563 × ) ÷ (0.0047)
= 1.8579 × 
÷ 0.0047
= 0.0003951 m
d = 0.00040 m
The width of the slit is 0.4 mm (0.00040 m).
Represent the motion in the number line.
Movement to the east is movement to the negative side. Movement to the west is movement to the positive side.
Total displacement = -680m + 430m - 620m = -870m
Total displacement = 860m to the east.
