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photoshop1234 [79]
3 years ago
15

The intensity of a certain siren is 0.060 W/m^2 from a distance of 25 meters. What is the intensity of this siren at a distance

of 50 meters?
Physics
1 answer:
Nady [450]3 years ago
7 0
<h2>The intensity of siren is 0.015 W m⁻²</h2>

Explanation:

The intensity of sound is inversely proportional to the square of distance between source and the observer .

Thus Intensity at a distance 25 m  is I₁ ∝ \frac{1}{r_1^2}                               I

Similarly the intensity at a distance 50 m is I₂ ∝ \frac{1}{r_2^2}               II

Dividing II by I , we have

\frac{I_2}{I_1} = \frac{r_1^2}{r_2^2} = \frac{25^2}{50^2} = \frac{1}{4}

Thus I₂ = \frac{1}{4} x 0.06 =  0.015 W m⁻²

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our friend is constructing a balancing display for an art project. She has one rock on the left (ms=2.25 kgms=2.25 kg) and three
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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The torque produced by the pile of rocks is \tau = 35.63\ N \cdot m  

b

The distance of the single for equilibrium to occur is r_s =1.62 \ m

Explanation:

From the question we are told that

     The mass of the left rock is  m_s = 2.25 \ kg

     The mass of the rock on the right m_p = 10.1 kg

    The distance from  fulcrum to the center of the pile of rocks is  r_p = 0.360 \ m

   

Generally the torque produced by the pile of rock is mathematically represented as

           \tau = m_p * g * r_p

Substituting values

         \tau = 10.1 * 9.8  * 0.360                  

          \tau = 35.63\ N \cdot m      

Generally we can mathematically evaluated the distance of the the single rock that would put the system in equilibrium as follows

   The torque due to the single rock is

           \tau = m_s  * g * r_s

At equilibrium the both torque are equal

            35.63 = m_s * r_s * g

Making r_s the subject of the formula

             r_s = \frac{35.63 }{m_s * g}

Substituting values

            r_s = \frac{35.63 }{2.25 * 9.8}

            r_s =1.62 \ m

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Uranium has two naturally occurring isotopes. 238u has a natural abundance of 99.3% and 235u has an abundance of 0.7%. it is the
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The ration of the rms speed of 235uf6 to that of 238uf6 is 1.004.

The molecular mass of 235uf6 is 349, while that of 238uf6 is 352.

The rms speed is calculated as

v=√(3RT/m)

Thus the ratio rms speed of 235uf6 to 238uf6 is calculated as

r=√(352/349)=1.004

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The work function for a metal surface is 4.98 eV. What is the largest wavelength of light in nm that will produce photoelectrons
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Answer:\lambda =248.99 nm

Explanation:

Given

Work function\left ( \phi \right )=4.98\approx 1.602\times 10^{-19}\times 4.98

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\phi =\frac{hc}{\lambda }

\lambda =\frac{hc}{\phi }

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