All categories

2 years ago

Which of the following is considered a greenhouse gas?

1 answer:

4 0

The primary greenhouse gases are water vapor, carbon dioxide, methane, nitrous oxide, and ozone. So, the correct answer among these options is water vapor, that is considered to be a greenhouse gas.

You might be interested in

Hydrochloride acid +_________ zinc chloride +hydrogen

Klio2033 [76]

Answer:

Hydrochloride acid + Zinc = Zinc Chloride + Hydrogen

Explanation:

When Hydrochloride acid and Zinc react, it results in the formation of Zinc chloride and hydrogen.

Hope I helped

3 0

1 year ago

About 3% of the water on Earth is freshwater. Only about 40% of that freshwater is available for human use. Why is so much fresh

OverLord2011 [107]

Because the freshwater is polluted.

5 0

2 years ago

Read 2 more answers

A sample of gas in a cylinder as in the example in Part A has an initial volume of 48.0 L , and you have determined that it cont

masya89 [10]

Answer:

0.45 moles

Explanation:

The computation of the number of moles left in the cylinder is shown below:

As we know that

$\frac{n1}{V1} = \frac{n2}{V2}$

we can say that

$n2 = n1 \times \frac{V2}{V1}$

where,

n1 = 1.80 moles of gas

V2 = 12.0 L

And, the V1 = 48.0 L

Now placing these values to the above formula

So, the moles of gas in n2 left is

$= 1.80 \times \frac{12.0\ L}{48.0\ L}$

= 0.45 moles

We simply applied the above formulas so that the n2 moles of gas could arrive

5 0

2 years ago

Which is least likely to be reduced? A. Zn^2+ B. Fe^3+ C. Cu^2+ D. Fe^2+

alekssr [168]

A. Zn²⁺

<h3>Further explanation</h3>

Given

Cations of several elements

Required

The least to be reduced

Solution

If we look at the voltaic series:

Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe²⁺-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Fe³⁺-Ag-Pt-Au

The electrode which is easier to reduce than the hydrogen (H2) electrode has a positive sign (E red= +) and is located to the right of the voltaic series (right of H)

The electrode which is easier to oxidize than the hydrogen (H2) electrode and is difficult to experience reduction has a negative sign (E red= -) and is located to the left of the voltaic series (left of H)

Or you can look at the standard reduction potential value of the metals in the answer options, and the most negative reduction E° value which will be difficult to reduce.

The Zn metal is located far left of the other metals in the answer choices, so it is the most difficult to reduce

6 0

2 years ago

Write the expression for the equilibrium constant for the reaction represented by the equation CaCO3(s)⇌Ca2+(aq)+CO32−(aq). Is K

Alexeev081 [22]

Answer: For the given reaction, the value of $K_c$ is greater than 1

Explanation:

For the given chemical equation:

$CaCO3(s)\rightleftharpoons Ca^{2+}(aq.)+CO_3^{2-}(aq.)$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[Ca^{2+}]\times [CO_3^{2-}]}{[CaCO_3}]\\\\K_c=[Ca^{2+}]\times [CO_3^{2-}]$

The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression

As, the denominator is missing and the numerator is the only part left in the expression. So, the value of $K_c$ will be greater than 1.

Hence, for the given reaction, the value of $K_c$ is greater than 1

5 0

3 years ago