Question

The maker of an automobile advertises that it takes 8 seconds to accelerate from 15 kilometers per hour to 70 kilometers per hour. Assuming constant acceleration, compute the distance, in meters, the car travels during the 8 seconds. Round your answer to two decimal places.

Answer 1

Answer:

The distance the car traveled during the given time is 94.44 m.

Explanation:

Given;

time of motion t = 8 seconds

initial velocity, u = 15 km/hr = 4.167 m/s

final velocity, v = 70 km/hr = 19.444 m/s

The distance traveled by the car during this time is given by;

$s = (\frac{u+v}{2} )t\\\\s = (\frac{4.167+19.444}{2} )*8\\\\s = 94.44 \ m$

Therefore, the distance the car traveled during the given time is 94.44 m.