I believe it would be 60*3.5. I apologize if this information is wrong.
Answer:
v = 31.3 m / s
Explanation:
The law of the conservation of stable energy that if there are no frictional forces mechanical energy is conserved throughout the point.
Let's look for mechanical energy at two points, the highest where the body is at rest and the lowest where at the bottom of the plane
Highest point
Em₀ = U = m g y
Lowest point
= K = ½ m v²
As there is no friction, mechanical energy is conserved
Em₀ =
m g y = ½ m v²
v = √ 2 g y
Where we can use trigonometry to find and
sin 30 = y / L
y = L sin 30
Let's replace
v = RA (2 g L sin 30)
Let's calculate
v = RA (2 9.8 100.0 sin30)
v = 31.3 m / s
In physics, the rate of power in Watts could be determined by multiplying the voltage in volts, by the current in Amperes. In equation, that would be
P = IV
Substituting the values into the equation,
60 W = I*12V
I = 60/12
I = 5 Amperes
Therefore, a current of 5 Amperes is passing through the yellow wire.
Answer:
39)
a) distance traveled = 1 mile
b) displacement = 0 mile
40) - 4 (m/s)
41-) distance traveled = 5 [m]
displacement = 3.6 [m]
Explanation:
The distance differs from the displacement, the distance traveled is equal to the sum of all displacements made by the particle or object.
Displacement is the difference between the initial point and the final point where the object or particle was stopped.
Then we can use the equation given:
The minus sign means the particle is slowing down.
For the 41) we can see the attached image.
In the graph we can see that the particle moves north 3 miles, so that the first distance is 3 miles, then moves 2 miles east being the second distance of 2 miles. Thus the sum of the distances is 3 + 2 = 5 miles.
Displacement is the difference between the endpoint and the initial point since the form of displacement is a straight line, we can use the formula of the straight line or the theorem of Pythagoras.
Answer:
The correct solution is "11.51 mA".
Explanation:
Given:
Time average power,
n = 377
As we now,
⇒
or,
⇒
⇒
hence,
⇒
By putting the values, we get