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ohaa [14]
4 years ago
11

Which of the following describes the genotype and phenotype of parents whose child will definitely have a recessive trait? A. Bo

th parents are homozygous for the recessive allele and have the trait. B. Both parents are homozygous for the recessive allele but do not have the trait. C. Both parents are heterozygous for the recessive allele and have the trait. D. Both parents are heterozygous for the recessive allele but do not have the trait.

Chemistry
1 answer:
viva [34]4 years ago
3 0

The answer is; A


When both parents are homozygous recessive, then there is 99.9 percent chances that offspring will bear the recessive trait. The offspring will also be homozygous recessive. This can be demonstrated by the following punnet square (assume dominant allele is assigned letter B while recessive allele b).


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Suppose that 5.14 x 10-3 mol of hydrogen gas occupies a 1,171 mL container at 60°C. What is the pressure (in torr)? (Do not type
Maru [420]

Answer:

<h2>91.2</h2>

Explanation:

Given that:

Temperature = 60 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (60 + 273.15) K = 333.15 K  

n = 5.14 × 10⁻³ mol

V = 1,171 mL = 1.171 L ( 1 mL = 0.001 L)

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.364 L Torr/ K mol  

Applying the equation as:

P × 1.171 L = 5.14 × 10⁻³ mol × 62.364 L Torr/ K mol  × 333.15 K  

<u>⇒P = 91.2 torr</u>

5 0
3 years ago
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Explanation:

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2 years ago
A particular reactant decomposes with a half‑life of 109 s when its initial concentration is 0.280 M. The same reactant decompos
Sophie [7]

Answer:

The order of reaction is 2.

Rate constant is 0.0328 (M s)⁻¹

Explanation:

The rate of a reaction is inversely proportional to the time taken for the reaction.

As we are decreasing the concentration of the reactant the half life is increasing.

a) For zero order reaction: the half life is directly proportional to initial concentration of reactant

b) for first order reaction: the half life is independent of the initial concentration.

c) higher order reaction: The relation between half life and rate of reaction is:

Rate = \frac{1}{k[A_{0}]^{(n-1)}}

Half life =K\frac{1}{[A_{0}]^{(n-1)} }

\frac{(halflife_{1})}{(halflife_{2})}=\frac{[A_{2}]^{(n-1)}}{[A_{1}]^{(n-1)} }

where n = order of reaction

Putting values

\frac{109}{231}=\frac{[0.132]^{(n-1)}}{[0.280]^{(n-1)}}

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Hence n = 2

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231=\frac{1}{K(0.132)}

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4 0
3 years ago
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