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Neko [114]
3 years ago
11

A car travels from Bangalore to Mumbai and returns back on 20 hrs. What is the average velocity and average speed of the car if

odometer reading of the car, when it started was 2200 km and when finished was 3800 km?
Physics
2 answers:
irinina [24]3 years ago
7 0

Answer:

Explanation:

Average speed= Total distance/ Total time

                        

Initial reading= 2200

final reading= 3800

total distance= Final reading -initial reading  = 3800-2200 = 1600 km

total time= 20 hrs

Average speed= 1600/20

                        = 80 km/hr

CONVERTING km/hr TO m/s  

To convert km/hr to m/s just multiply

Recall that,

1000m = 1 km

60 secs = 1 min

60 mins = 1 hr

( 80 × 1000 ) meters / ( 60×60 ) secs

80000m / 3600s

= 22.22m/s

Shtirlitz [24]3 years ago
4 0

Answer:

Average speed = 80 km/hr

Average velocity = 0 km/hr

Explanation:

Average velocity is given by

Average velocity = Displacement / Time taken

And Average speed is given by

Average speed = Total distance / Time taken

To calculate the average speed, we will first find the total distance,

Total distance = Final reading of the odometer - Initial reading of the odometer

Hence,

Total distance = 3800km - 2200km

Total distance = 1600km

From the question, the time taken = 20hrs

Therefore,

Average speed = 1600km ÷ 20hrs

Average speed = 80 km/hr

To calculate the average velocity, we will find the displacement.

Displacement is the distance traveled in a straight line OR the shortest distance from the initial to the final position.

Since the car returned back to its initial position (Bangalore), the displacement is zero.

From,

Average velocity = Displacement / Time

Hence,

Average velocity = 0 ÷ 20

Average velocity = 0 km/hr

The average velocity is 0 km/hr

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