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irina [24]
4 years ago
12

Quanto vale a resultante de duas forças de mesmo módulo mesma direção e sentidos opostos atuando sobre um corpo de massa igual a

2 kg qual é o valor da aceleração desse corpo nessas condições
Physics
2 answers:
Crank4 years ago
6 0
A resultante das duas forças será zero, já q os sentidos são opostos e sãos iguais em módulo, elas se anulam. Logo, se a força resultante é zero, e F=ma, aceleração também será igual a zero.
Anton [14]4 years ago
6 0

Answer:

This question is in Portuguese, this means:

"How much is the result of two forces of the same module in the same direction and opposite ways acting on a body with a mass equal to 2 kg? what is the value of the acceleration of that body in these conditions?"

Now, i will answer in English.

When we are doing math with forces, we can use "Linear overlay", this means that we can add an subtract the forces between them.

Now, if you apply two forces of the same magnitude and same direction but in opposite ways (one is pointing in x positive and the other in x negative) we can directly add them:

F*(+x) + F(-x) = F(+x) - F(+x) = 0

Where (+x) and (-x) refer to the direction at which the forces are applied,

and it has sense, if you pull with the same force by opposite sides, the total force that the object suffers is zero.

And because the total force that the object suffers is zero, by the second Newton's equation f*m = a, the acceleration that the object suffers is also zero.

You might be interested in
A constant net force of 345 N is applied to slide a heavy stationary
liubo4ka [24]

Answer:

P = 517.5 [kg*m/s]

Explanation:

We must remember that momentum is defined as the product of force by the time of force duration.

P=F*t

where:

P = momentum [kg*m/s]

F = force [N]

t = time [s]

P=345*1.5\\P=517.5[kg*m/s]

4 0
3 years ago
Three carts of masses 4.0 kg, 10kg, and 3.0 kg move on a frictionless track with speeds of v1 = 5.0m/s, v2=3.0m/s, and v3=-3.6 m
gogolik [260]

2.24 m/s is the calculated velocity.

Initial velocity (u) squared plus two times the acceleration (a) times the displacement equals final velocity (v) squared (s). Final velocity (v) is equal to the square root of initial velocity (u) squared plus two times the acceleration (a) times displacement when v is the variable being solved for (s).

The cart's masses and speeds are known.

M1 = 4.00 kg, M2 = 10.0 kg, M3 = 3.00 kg, etc.

v1 = 5.00 m/s = 5.00 m/s, v2 = 3.00 m/s = 3.00 m/s, v3 = -4.00 m/s = 4.00 m/s, and m1v1+m2v2+m3v3 = (m1+m2+m3) v=d frac m 1v 1+m 2v 2+m 3v 3, where (m1+m2 + m3) is the product of (v1 v 1+m2v2+m3v3).

"m 1+m 2+m 3" is equivalent to "m 1+m2+m3/m1v 1+m2v2 +m3v3"

the three carts' final velocities are calculated as follows: v=d frac

{4.00kg\sdot5.00m/s+10.0kg\sdot3.00m/s-3.00kg\sdot4.00m/s} 4.24m/s = 4.50kg+10.0kg+3.00kg vs. 4.50kg+10.0kg+3.00kg

5.00m/s/4.00kg/5.00m/s+10.0m/s/3.00m/s/4.00m/s =2.24m/s.

2.24 m/s is the calculated final velocity.

Learn more about velocity here-

brainly.com/question/18084516

#SPJ9

7 0
2 years ago
A wye-connected load has a voltage of 480v applied to it. What is the voltage drop across each phase
rodikova [14]

Answer:

Y_A=277.128 \angle 30v

Y_B=277.128 \angle (-150)v

Y_C=277.128 \angle (90)v

Explanation:

From the question we are told that

Voltage V_L_L =480v

Generally in a case of Y_connection V_p_ h is mathematical represented as

V_p_h=\frac{V_l_l}{\sqrt{3}} \angle (\phi-30)v

Generally voltage drop across phase A

Y_A=\frac{408}{\sqrt{3}} \angle -(0-30)

Y_A=277.128 \angle 30v

Generally voltage drop across phase B

Y_B=277.128 \angle (-30-120)

Y_B=277.128 \angle (-150)v

Generally voltage drop across phase C

Y_C=277.128 \angle (-30+120)

Y_C=277.128 \angle (90)v

3 0
3 years ago
If the heat of combustion for a specific compound is -1320.0 kJ/mol and its molar mass is 71.83 g/mol, how many grams of this co
natka813 [3]
Heat released from combustion is calculated by multiplying the amount of substance being burned with its heat of combustion. From this, we can calculate the mass needed from the system above. The calculation is as follows:

-543 kJ = x x -1320 kJ/mol
x = 0.411 mol 

Mass of x = 0.411 x 71.83 g/mol
Mass of x = 29.55 g 
4 0
4 years ago
Does volume affect potential energy
Andrej [43]

Answer:

No, the volume don't affect the potential energy.

Explanation:

The volume does not affect the potential energy, as this energy depends on the mass and elevation of the body relative to the reference point. This analysis can be easily seen in the equation expressing potential energy

E_{p} =m*g*h\\where:\\m=mass[kg]\\g=gravity[m/^2]\\h=elevation[m]

3 0
4 years ago
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