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irina [24]
3 years ago
12

Quanto vale a resultante de duas forças de mesmo módulo mesma direção e sentidos opostos atuando sobre um corpo de massa igual a

2 kg qual é o valor da aceleração desse corpo nessas condições
Physics
2 answers:
Crank3 years ago
6 0
A resultante das duas forças será zero, já q os sentidos são opostos e sãos iguais em módulo, elas se anulam. Logo, se a força resultante é zero, e F=ma, aceleração também será igual a zero.
Anton [14]3 years ago
6 0

Answer:

This question is in Portuguese, this means:

"How much is the result of two forces of the same module in the same direction and opposite ways acting on a body with a mass equal to 2 kg? what is the value of the acceleration of that body in these conditions?"

Now, i will answer in English.

When we are doing math with forces, we can use "Linear overlay", this means that we can add an subtract the forces between them.

Now, if you apply two forces of the same magnitude and same direction but in opposite ways (one is pointing in x positive and the other in x negative) we can directly add them:

F*(+x) + F(-x) = F(+x) - F(+x) = 0

Where (+x) and (-x) refer to the direction at which the forces are applied,

and it has sense, if you pull with the same force by opposite sides, the total force that the object suffers is zero.

And because the total force that the object suffers is zero, by the second Newton's equation f*m = a, the acceleration that the object suffers is also zero.

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As atoms in the spoon vibrates about their equilibrium positions and transfer energy form one end to other end. This process is called conduction.

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3 years ago
Stop to Think 7.1 Which one is greater- the attraction of the Earth on 1 kg lead or the attraction of 1 kg of led
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Answer:

1 kg lead to earth is greater attraction as mass of earth is much more than 1kg lead.

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Apparent weightlessness

Explanation:

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A spring of spring constant 30.0 N/m is attached to a 2.3 kg mass and set in motion. What is the period and frequency of vibrati
coldgirl [10]

Answer:

1. The period is 1.74 s.

2. The frequency is 0.57 Hz

Explanation:

1. Determination of the the period.

Spring constant (K) = 30 N/m

Mass (m) = 2.3 Kg

Pi (π) = 3.14

Period (T) =?

The period of the vibration can be obtained as follow:

T = 2π√(m/K)

T = 2 × 3.14 × √(2.3 / 30)

T = 6.28 × √(2.3 / 30)

T = 1.74 s

Thus, the period of the vibration is 1.74 s.

2. Determination of the frequency.

Period (T) = 1.74 s

Frequency (f) =?

The frequency of the vibration can be obtained as follow:

f = 1/T

f = 1/1.74

f = 0.57 Hz

Thus, the frequency of the vibration is 0.57 Hz

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3 years ago
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