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arsen [322]
3 years ago
6

The LR5 is the specialist submarine for underwater rescue. The average density of seawater is 1028 kg/ m3.

Physics
1 answer:
sladkih [1.3K]3 years ago
5 0

Answer:

P = 7196 [kPa]

Explanation:

We can solve this problem using the expression that defines the pressure depending on the height of water column.

P = dens*g*h

where:

dens = 1028 [kg/m^3]

g = 10 [m/s^2]

h = 700 [m]

Therefore:

P = 1028*10*700

P = 7196000 [Pa]

P = 7196 [kPa]

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Why is it better to use the metric system, rather than the English system, in scientific measurement?
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A. The English system uses one unit for each category of measurement.

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3 years ago
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HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!<br> I NEED THE ANSWER NOW
FrozenT [24]
90 F = 43 OR 0.9F = 0.43
(F = 43 / 90 OR 0.43 / 0.9 =) 0.48 N

upwards force = downwards force
(R =) 1.2 N
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3 years ago
An airplane takes off at an angle of 75° from its starting point. when the plane has traveled a total distance of 600 feet, its
Alexxandr [17]
Draw a right triangle so that its hypotenuse is 600 ft. The adjacent side is below the vertical, and it makes an angle of 75° with the hypotenuse.

Let h =  height of the right triangle.
By definition,
sin75° = h/600
h = 600*sin75° = 579.555 = 580 ft (nearest ft)

Answer: 580 ft (nearest foot)
7 0
3 years ago
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As the captain of the scientific team sent to Planet Physics, one of your tasks is to measure g. You have a long, thin wire labe
spin [16.1K]

Answer:

1.19 m/s²

Explanation:

The frequency of the wave generated in the string in the first experiment is f = n/2l√T/μ were T = tension in string = mg were m = 1.30 kg weight = 1300 g , μ = mass per unit length of string = 1.01 g/m. l = length of string to pulley = l₀/2 were l₀ = lent of string. Since f is the second harmonic, n = 2, so

f = 2/2(l₀/2)√mg/μ = 2(√mg/μ)/l₀    (1)

Also, for the second experiment, the period of the wave in the string is T = 2π√l₀/g. From (1) l₀ = 2(√mg/μ)/f and from (2) l₀ = T²g/4π²

Equating (1) and (2) we ave

2(√mg/μ)/f = T²g/4π²

Making g subject of the formula

g = 2π√(2√(m/μ)/f)/T

The period T = 316 s/100 = 3.16 s

Substituting the other values into , we have

g = 2π√(2√(1300 g/1.01 g/m)/200 Hz)/3.16

g = 2π√(2 × 35.877/200 Hz)/3.16

g = 2π√(71.753/200 Hz)/3.16

g = 2π√(0.358)/3.16

g = 2π × 0.599/3.16

g = 1.19 m/s²

6 0
3 years ago
(20 points) Pressure is a measure of force per unit area or P=F/A. A student is checking the amount of pressure their car exerts
Gala2k [10]

Answer:

35.2 ps

Explanation:

Hello!

A US short ton is equal to 2 000 pounds, therefore:

2.25 tons = 4500 pounds

Now lets convert the area of each tire footprint:

1 cm = 0.393701 in

12.5 cm = 4.92126 in

16.5 cm = 6.49607 in

Therefore, the area of the footprint is:   31.9688 in^2

Then, the pressure exerted by the car is given by the weigth devided by the total area, that is 4 times the area of the footprint :

4500 /(4 * 31.9688)  psi = 35.1906 psi

Rounding to the first tenth

35.2 psi

6 0
3 years ago
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