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3 years ago

8

If 20N force produces an acceleration of 5ms^-2 In a body then the mass of the body will be:

1 answer:

meriva3 years ago

5 0

F = ma
m = F/a
m = 20N / 5m/s^2
m = 4kg

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In a thundercloud there may be an electric charge of 41 C near the top of the cloud and −41 C near the bottom of the cloud. If t

Andre45 [30]

Answer:

F = 236063.6N

Explanation:

Please see attachment below.

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3 years ago

( 8c5p79) A certain force gives mass m1 an acceleration of 13.5 m/s2 and mass m2 an acceleration of 3.5 m/s2. What acceleration

Talja [164]

Answer:

$4.725 m/s^{2}$

Explanation:

We know that from Newton's second law of motion, F=ma hence making acceleration the subject then $a=\frac {F}{m}$ where a is acceleration, F is force and m is mass

Also making mass the subject of the formula $m=\frac {F}{a}$

For $m1= \frac {F}{13.5}$ and $m2=\frac {F}{3.5}$ hence $F=(m2-m1)a= (\frac {F}{3.5}-\frac {F}{13.5})a=0.2116402116\\\frac {1}{a}=0.2116402116\\a=4.725 m/s^{2}$

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3 years ago

You are camping with two friends, Joe and Karl. Since all three of you like your privacy, you don't pitch your tents close toget

aleksklad [387]

Answer:

35.7 m

Explanation:

Let

$\mid A\mid=18.5 m$

$\mid B\mid=41 m$

We have to find the distance between Joe's and Karl'e tent.

$A_x=Acos\theta$

$A_y=Asin\theta$

Substitute the values then we get

$A_x=18.5cos23^{\circ}=17 m$

$A_y=18.5sin 23^{\circ}=7.2 m$

$B_x=41cos37.5^{\circ}=32.5 m$

$B_y=41sin37.5^{\circ}=-24.96 m$

Because vertical component of B lie in IV quadrant and y-inIV quadrant is negative.

By triangle addition of vector

$B=A+C$

$C=B-A$

$C_x=B_x-A_x=32.5-17=15.5 m$

$C_y=B_y-A_y=-24.96-7.2=-32.16\approx=-32.2 m$

$\mid C\mid=\sqrt{C^2_x+C^2_y}$

$\mid C\mid=\sqrt{(15.5)^2+(-32.2)^2}=35.7 m$

Hence, the distance between Joe's and Karl's tent=35.7 m

6 0

3 years ago

How do I delete a question on here

EastWind [94]

I don’t think you can :((

7 0

3 years ago

Read 2 more answers

At the surface of Jupiter's moon Io, the acceleration due to gravity is 1.81 m/s2 . A watermelon has a weight of 54.0 N at the s

butalik [34]

Answer:

$m=5.51Kg$

Explanation:

The weight of an object on Earth is given by $W=mg$ , so we can calculate its mass by doing $m=W/g$ , which for our values is:

$m=(54N)/(9.8m/s^2)=5.51Kg$

<em>Nothing is being asked</em> about Io but if one wanted to know the weight <em>W'</em> of the watermelon there one just have to do:

$W'=ma=(5.51Kg)(1.81m/s^2)=9.97N$

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3 years ago