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weqwewe [10]
3 years ago
8

If 20N force produces an acceleration of 5ms^-2 In a body then the mass of the body will be:

Physics
1 answer:
meriva3 years ago
5 0
F = ma
m = F/a
m = 20N / 5m/s^2
m = 4kg
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Pachacha [2.7K]

 

Mine tailings be stored and disposed of carefully since they contain a lot of chemicals that are very toxic that leaches into aquifers, and they also runoff in the rainwater into streams and lakes.

Tailings, also called mine <span>dumps, culm dumps, slimes, tails, refuse, leach residue or slickens, are the materials left over after the process of separating the valuable fraction from the uneconomic fraction (gangue) of an ore.</span>

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3

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6 0
3 years ago
when two resistors are wired in series with a 12 v battery, the current through the battery is 0.31 a. when they are wired in pa
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Let  R₁  and R₂ be the  two Resistance

R₁ - Resistance of 1st resistor

R₂ - Resistance of 2nd resistor

V = Voltage = 12V

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I  = 1.6 A ( in parallel)

when two resistance connected in series

Rs = R₁ + R₂

V = IRs = 12 /0.31 V

R₁+R₂ = 38.700Ω   (equation1.)

When two resistance connected in parallel

    R_{p} =\frac { R_{1} R_{2}}{R_{1} + R_{2}  }

V = I Rp

V=  I (R₂ R₁ /R₁ +R₂)

R₁ R₂ = 290.25 Ω  

As we know

(R₁ - R₂ ) ² = (R₁ + R₂ ) ² - 4R1R2

Using above values we get,

 (R₁ - R₂ ) ²  = (38.70) ²  - 4x 290.25

 (R₁ - R₂ ) ²   = 336.69  Ω  

R₁ - R₂ = 18.34     (equation 2 )

Using equation 1 and 2 we get

R₁+ R₂ = 38.70 52

R₁ - R₂ = 18.34

R₁ = 28.535 Ω  

Using the value of  R₁ in equation 1 we get

R₂ = 38·700 -  28.535

RR₂ = 10.125 Ω  

R₁ = 28. 535 v  and   R₂  10.125 Ω  

To know more about resistance in series and parallel:

brainly.com/question/27882579

#SPJ4

7 0
1 year ago
Two identical satellites orbit the earth in stable orbits. one satellite orbits with a speed v at a distance r from the center o
wariber [46]
The available options are: (found the complete text on internet)
A- at a distance less than r
B- at a distance equal to r
C- at a distance greater than r

Solution:
The correct answer is C) at a distance greater than r.

In fact, the gravitational attraction between the satellite and the Earth provides the centripetal force that keeps the satellite in circular orbit, so we can write
G \frac{Mm}{r^2}=m \frac{v^2}{r}
where the term on the left is the gravitational force, while the term on the right is the centripetal force, and where
G is the gravitational constant
M is the Earth mass
m is the satellite mass
r is the distance of the satellite from the Earth's center
v is the satellite speed

Re-arranging the equation, we get
r= \frac{GM}{v^2}
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7 0
3 years ago
In the most common isotope of Hydrogen the nucleus is made out of a single proton. When this Hydrogen atom is neutral, a single
FinnZ [79.3K]

Answer:

The ratio of electric force to the gravitational force is 2.27\times 10^{39}

Explanation:

It is given that,

Distance between electron and proton, r=4.53\ A=4.53\times 10^{-10}\ m

Electric force is given by :

F_e=k\dfrac{q_1q_2}{r^2}

Gravitational force is given by :

F_g=G\dfrac{m_1m_2}{r^2}

Where

m_1 is mass of electron, m_1=9.1\times 10^{-31}\ kg

m_2 is mass of proton, m_2=1.67\times 10^{-27}\ kg

q_1 is charge on electron, q_1=-1.6\times 10^{-19}\ kg

q_2 is charge on proton, q_2=1.6\times 10^{-19}\ kg

\dfrac{F_e}{F_g}=\dfrac{kq_1q_2}{Gm_1m_2}

\dfrac{F_e}{F_g}=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{6.67\times 10^{-11}\times 9.1\times 10^{-31}\times 1.67\times 10^{-27}}

\dfrac{F_e}{F_g}=2.27\times 10^{39}

So, the ratio of electric force to the gravitational force is 2.27\times 10^{39}. Hence, this is the required solution.

3 0
3 years ago
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