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DerKrebs [107]
3 years ago
6

I need some help pls

Physics
1 answer:
Lina20 [59]3 years ago
4 0

Answer:

And the bigger intensity

Explanation:

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Name these polyatomic compounds
beks73 [17]
1) calcium sulfate
2) potassium carbonate
3) Copper Nitrate
4) Ammonium Chloride
5) Magnesium Nitrate
6) Potassium Phosphate
7) Lithium Chromate
8) Magnesium Hydroxide
9) Aluminum Phosphate
10) potassium Nitrate
11) Calcium Sulfite
6 0
3 years ago
Read 2 more answers
Derive the following equations of motion
xz_007 [3.2K]

Answer:

___________________________________

<h3>a. Let us assume a body has initial velocity 'u' and it is subjected to a uniform acceleration 'a' so that the final velocity 'v' after a time interval 't'. Now, By the definition of acceleration, we have:</h3>

a =  \frac{v - u}{t}  \\ or \: at = v - u \\ v = u + at \:

It is first equation of motion.

___________________________________

<h3>b. Let us assume a body moving with an initial velocity 'u'. Let it's final body 'v' after a time interval 't' and the distance travelled by the body becomes 's' then we already have,</h3>

v = u + at...........(i) \\ s =  \frac{u + v}{2}  \times t.........(ii)

Putting the value of v from the equation (i) in equation (ii), we have,

s=  \frac{u + (u + at)}{2}  \times t \:  \: \\ or \: s =  \frac{(2u + at)t}{2}  \\ or \: s =  \frac{2ut + a {t}^{2} }{2}  \\ s = ut +  \frac{1}{2} a {t}^{2}

It is third equation of motion.

________________________________

<h3>c. Let us assume a body moving with an initial velocity 'u'. Let it's final velocity be 'v' after a time and the distance travelled by the body be 's'. We already have,</h3>

v = u + at.....(i) \\ s =  \frac{u + v}{2}  \times t......(ii) \\

v = u + at \\ or \: at = v - u \\ t =  \frac{v - u}{a}

Putting the value of t from (i) in the equation (ii)

s =  \frac{u + v}{2}  \times  \frac{v - u}{a}  \\ or \: s =   \frac{ {v}^{2}  -  {u}^{2} }{2a}  \\ or \: 2as =  {v}^{2}  -  {u}^{2}  \\  {v}^{2}  =  {u}^{2}  + 2as

It is forth equation of motion.

________________________________

Hope this helps...

Good luck on your assignment..

3 0
3 years ago
A 30 resistor is connected in series with another resistor and a 6. 0V battery. The current in th
Setler79 [48]

Hi there!

We can begin by calculating the voltage drop across the 30 Ω resistor using the equation:

V = IR
V = Potential Difference (V)

I = Current (A)

R = Resistance (Ω)

Calculate the voltage. Recall that the current is CONSTANT across a series circuit.


V = 0.12 × 30 = 3.6 V

Voltage ADDS UP in a series, so:

Total V = V1 + V2

6 = 3.6 + V2

<u>V2 = 2.4V. The correct answer is A.</u>

6 0
2 years ago
If the solar system shrank so that the sun were located just one centimeter from Earth, about how far away could you find the ne
DedPeter [7]
E                  S                                                               *

The "E" represents Earth, "S" represent Sun, and the "*" represents the nearest star(which is Proxima Centauri).

The main thing to worry about here is units, so ill label everything out.
D'e,s'(Distance between earth and sun) = .<span>00001581 light years
D'e,*'(Distance between earth and Proxima) = </span><span>4.243 light years

Now this is where it gets fun, we need to put all the light years into centimeters.(theres alot)
In one light year, there are </span>9.461 * 10^17 centimeters.(the * in this case means multiplication) or 946,100,000,000,000,000 centimeters.

To convert we multiply the light years we found by the big number.
D'e,s'(Distance between earth and sun) = 1.496 * 10^13 centimeters<span>
D'e,*'(Distance between earth and Proxima) = </span><span>4.014 * 10^18 centimeters
</span>
Now we scale things down, we treat 1.496 * 10^13 centimeters as a SINGLE centimeter, because that's the distance between the earth and the sun. So all we have to do is divide (4.014 * 10^18 ) by (<span>1.496 * 10^13 ).
Why? because that how proportions work.

As a result, you get a mere 268335.7 centimeters.

To put that into perspective, that's only about 1.7 miles

A lot of my numbers came from google, so they are estimations and are not perfect, but its hard to be on really large scales.</span>
8 0
3 years ago
A father pushes his child in a cart. The cart starts to move.
LuckyWell [14K]

The potential energy of the car when it let go is 20,000 J.

The speed of the car at the bottom of the ramp is 20 m/s.

The given parameters;

  • <em>mass of the car, m = 100 kg</em>
  • <em>height of the car, h = 20 m</em>

<em />

The potential energy of the car is calculated as follows;

P.E = mgh

P.E = 100 x 10 x 20

P.E = 20,000 J

The speed of the car at the bottom of the ramp is calculated as follows;

K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2 \times 10 \times 20} \\\\v = 20 \ m/s

Learn more here:brainly.com/question/18597080

5 0
3 years ago
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