Given :
Height from which ball is dropped , h = 40 m .
Acceleration due to gravity , g= 10 m/s² .
Initial velocity , u = 0 m/s .
To Find :
Velocity when ball covered 20 m and velocity when it hit the ground .
Solution :
Now , height when ball covered 20 m distance is , 40 - 20 = 20 m .
By equation of motion :
Now , distance covered when body reaches ground is , 40 m .
Putting value h = 40 m in above equation , we get :
Hence , this is the required solution .
Motion must be defined relative to something.
Here's an obvious, everyday example:
-- You're in a passenger jet, going to visit grandma on the
coast for the holidays.
-- You're sitting still in your seat, listening to some 'mp3's,
reading a book, and dozing off.
-- At the same time, people on the ground see you flying over
at almost 500 miles per hour.
Are you moving at 500 mph, or are you not moving at all ?
The answer is 'Yes. Both.'. It just depends on who's measuring your speed.
There's no such thing as your "real" speed. Motion is always
relative to something. Different reference = different speed.
Answer:
Explanation:
As we projected the balloon at speed vo at an angle of 29 degree
so the two component of velocity is given as
now we know that in x direction we have
in y direction we have
now we have
The object is not accelerating. I think I got this question right