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NARA [144]
4 years ago
6

Write a balanced chemical equation for the fermentation of sucrose (C12H22O11) by yeasts in which the aqueous sugar reacts with

water to form aqueous ethyl alcohol (C2H5OH) and carbon dioxide gas.
Chemistry
1 answer:
bogdanovich [222]4 years ago
4 0

Answer:

C_{12}H_{22}O_{11}(aq)+H_{2}O(aq)=4C_{2}H_{5}OH(aq)+4CO_{2}(g)

Explanation:

1. First write the formula of each compound:

Sucrose : C_{12}H_{22}O_{11}

Water : H_{2}O

Ethyl alcohol : C_{2}H_{5}OH

Carbon dioxide : CO_{2}

2. Write the equation with the reactants on the left and the products on the right:

C_{12}H_{22}O_{11}+H_{2}O=C_{2}H_{5}OH+CO_{2}

3. Put the states of matter of each compound in the reaction, as the problem says:

C_{12}H_{22}O_{11}(aq)+H_{2}O(aq)=C_{2}H_{5}OH(aq)+CO_{2}(g)

aq = aqueous solution

g =  gas

4. Balance each element.

The number of each atom must be the same on the left and on the right.

C_{12}H_{22}O_{11}(aq)+H_{2}O(aq)=4C_{2}H_{5}OH(aq)+4CO_{2}(g)

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References Use the References to access important values if needed for this question A student ran the following reaction in the
ANTONII [103]

Answer:

19.27

Explanation:

Some values are corrected from correct source.Thus,

Moles of SO₂ = 8.19x10⁻² moles

Moles of O₂ = 8.10x10⁻² moles

Volume = 1 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Concentration of SO₂ = 8.19x10² M

Concentration of O₂ = 8.10x10 M

Considering the ICE table for the equilibrium as:

                    2SO₂ (g) +    O₂ (g)     ⇔          2SO₃ (g)

t = o              8.19x10⁻²      8.19x10⁻²

t = eq                -2x                  -x                      2x

--------------------------------------------- --------------------------

neq:    8.19x10⁻² -2x       8.19x10⁻² -x                      2x

Given:  

Equilibrium concentration of  O₂ = 5.98x10⁻² M  = 8.19x10⁻² -x

Thus, x = 0.0212 M

[SO₂] = 8.19x10⁻² - 2*0.0212 = 0.0395 M

[SO₃] = 2*0.0212 = 0.0424 M

The expression for the equilibrium constant is:

K_c=\frac {[SO_3]^2}{[SO_2]^2[O_2]}  

K_c=\frac{{0.0424}^2}{{0.0395}^2\times 0.0598}  

K = 19.27

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