Answer:
The wavelength of the radio wave is 3.003 m.
The energy of the radio wave is
.
Explanation:
Frequency of the radio waves, ν = 99.9 MHz = 
Wavelength and frequency are related to each other by realtion:

= Wavelength of the wave
c = speed of the light
ν = Frequency of the wave

The wavelength of the radio wave is 3.003 m.
The energy of the electromagnetic wave is given by Planck's equation:

h = Planck's constant = 
The energy of the radio wave with 99.9 MHz frequency will be:


The energy of the radio wave is
.
Answer:
Diffusion occurs in solid and liquid through the constant and random motion of the smaller particles called molecules of either solid, liquid or gaseous in permeable medium as witnessed in the experiment.
Explanation:
The kinectic molecular theory of matter states that the smaller particles of matters called molecules are in constant, but random motion and the degree of movement of the molecules depends on the state or phase such matter exist, which is a derivative of the total kinetic energy possessed by the molecules. This average kinetic energy of the molecules as iodine for example is proportional to the temperature of the matter.
Diffusion should be remembered as the movement of molecules of matters from a highly concentrated region otherwise called hypertonic region to a less concentrated region called hypotonic region through a permeable medium until there is an equilibrium in the system. Since diffusion is expected to involve the movement of molecules, and any matter that can exhibit diffusion is said to have moving molecules, therefore, the kinetic molecular theory of matter is proven to be accurate with the observed movement of iodine molecules in the test tube. This shows that even the molecules of solid matters are in constant random motion, this is made more convincing when these molecules migrate without the addition of external energy source like heat, which then help to understand that the natural iodine molecules are in constant random motion, as they are changed to gaseous state without passing through liquid state, a phenomenon called sublimation.
<span>Mn's
atomic number is 25 so you have 25 protons and 25 electrons in a
neutral atom. Since no charge is shown, the number of electrons is 25
Ni's atomic number is 28 so you have 28 protons and 28 electrons in a
neutral atom. This one shows a +3 so there are 3 missing electrons, the
number of electrons is 28 - 3 = 25
Cu's atomic number is 29 so you have 29 protons and 29 electrons in a
neutral atom. This one shows a +2 so there are 2 missing electrons, the
number of electrons is 29 - 2 = 27
Ti's atomic number is 22 so you have 22 protons and 22 electrons in a
neutral atom. This one shows a -2 so there are 2 EXTRA electrons, the
number of electrons is 22 + 2 = 24 </span>
Sample means for solutions 1 and 2 are 19.27 and 10.32 respectively
In semiconductor manufacturing,
The total for answer 1 is given by:
9.7+10.5+9.4+10.6+9.3+10.7+9.6+10.4+10.2+10.5 = 192.7
The sample size is 10 and provides us with
192.7/10 = 19.27
For solution 2, the sum is given by:
10.6+10.3+10.3+10.2+10.0+10.7+10.3+10.4+10.1+10.3 = 103.2
The sample size is 10, this gives us
103.2/10 = 10.32
The total for answer 2 is given by:
10.6+10.3+10.3+10.2+10.0+10.7+10.3+10.4+10.1+10.3 = 103.2
The sample size is 10 and provides us with
103.2/10 = 10.32
Learn more about semiconductor manufacturing here brainly.com/question/22779437
#SPJ4.
In semiconductor manufacturing, wet chemical etching is often used to remove silicon from the backs of wafers prior to metalization. The etch rate is an important characteristic in this process and is known to follow a normal distribution. Two different etching solutions have been compared, using two random samples of 10 wafers for each solution. Assume the variances are equal. The etch rates are as follows (in mils per minute): Solution 1 Solution 2 9.7 10.6 10.5 10.3 9.4 10.3 10.6 10.2 9.3 10.0 10.7 10.7 9.6 10.3 10.4 10.4 10.2 10.1 10.5 10.3 Calculate sample means of solution 1 and solution 2
Answer:
P₂ = 1.0 atm
Explanation:
Boyles Law problem => P ∝ 1/V at constant temperature (T).
Empirical equation
P ∝ 1/V => P = k(1/V) => k = P·V => for comparing two different case conditions, k₁ = k₂ => P₁V₁ = P₂V₂
Given
P₁ = 1.6 atm
V₁ = 312 ml
P₂ = ?
V₂ = 500 ml
P₁V₁ = P₂V₂ => P₂ = P₁V₁/V₂ =1.6 atm x 312 ml / 500ml = 1.0 atm