Answer:
The diameter of the bull-wheel is 3.82
Explanation:
Given that,
Velocity = 2.0 m/s
Angular velocity = 10 rev/m
We need to calculate the diameter of bull-wheel
Using formula of angular velocity
Put the value into the formula
The diameter of the bull-wheel
Hence, The diameter of the bull-wheel is 3.82 m.
Answer:
B.) its velocity is zero and its acceleration is negative (downward).
Explanation:
When the ball is thrown upwards in the air, the ball starts with its velocity being high and positive upwards against the force of gravity. Due to force of gravity pulling the object to the center of the earth, its velocity decreases as it reaches the maximum height where the velocity is instantaneously zero. At this maximum height its acceleration is -9.81 m/s².
Answer:
a. 600 ml, 12
Explanation:
The movement described in the question exhibits that of a polygon. Exhibiting a constant distance and angle with only varying direction until the starting point is reached.
The sum of exterior angles of a polygon = 360 degrees.
Exterior angle of a polygon = (360 ÷ number of sides)
Therefore,
Number of sides = 360 ÷ exterior angle
Exterior angle = 30 degrees
Hence,
Number of sides = 360 ÷ 30 = 12 sides
Since distance traveled of 50 miles is the same for each displacement ;
Total displacement = distance traveled * number of sides
Total displacement = 50 * 12 = 600 miles.
Answer:
28 grams
Explanation:
The equation for the reaction is
3H(2) + N(2) -> 2NH(3)
Then we have.
The molar mass, M of ammonia is 17 g/mol.
34 grams of ammonia, NH3 then would be
34 g / 17 g/mol
= 2 moles
2 moles of ammonia will be obtained from
(2 * 1) / 2
= 1 mole of nitrogen
The molar masses of nitrogen is 28 g/mol
2 moles of nitrogen corresponds to 1 * 28 = 28 grams.
F= (speed)/(wavelength)
Therefore, speed = Frequency x wavelength
V = 68m/s
