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expeople1 [14]
3 years ago
6

Describe the forces that are acting on a person who is standing still on a sidewalk, and identify whether the forces are balance

d or unbalanced. Describe how the forces would change if the person started walking.
Physics
1 answer:
mr_godi [17]3 years ago
6 0

Answer:

a. i His weight and the normal force on him due to the ground

ii The weight and the normal force are balance

b. There are four forces acting on him while he is walking. These are the backward push due to his leg on the ground and the frictional force between his feet in the horizontal direction and, his weight and normal force on his feet in the vertical direction.

Explanation:

a. i Describe the forces that are acting on a person who is standing still on a sidewalk

His weight and the normal force on him due to the ground act on him while the person is standing on the sidewalk

ii. identify whether the forces are balanced or unbalanced.

The weight and the normal force are balance because, the person does not move in the vertical or horizontal direction.

b. Describe how the forces would change if the person started walking.

When the person starts walking, the backward push due to his leg on the ground and the frictional force between his feet and the ground now acts on him in the horizontal direction. The frictional force acts in the forward direction and tends to move him forward. His weight and normal force on his feet still act vertically and are both balanced since he does not move in the vertical direction.

<u>So, there are four forces acting on him while he is walking. These are the backward push due to his leg on the ground and the frictional force between his feet in the horizontal direction and, his weight and normal force on his feet in the vertical direction.</u>

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(a) How much work is required to lift a 35-kg object from the ground 3.0 m into the air? (b) How much gravitational potential en
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Answer:

(a) work required to lift the object is 1029 J

(b) the gravitational potential energy gained by this object is 1029 J

Explanation:

Given;

mass of the object, m = 35 kg

height through which the object was lifted, h = 3 m

(a) work required to lift the object

W = F x d

W = (mg) x h

W = 35 x 9.8 x 3

W = 1029 J

(b) the gravitational potential energy gained by this object is calculated as;

ΔP.E = Pf - Pi

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Pi is the initial gravitational potential energy, at initial height (hi = 0)

ΔP.E = (35 x 9.8 x 3) - (35 x 9.8 x 0)

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Why do surface winds tend to cross the isobars?
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The motion of a particle is defined by the relation x 5 t 3 2 9t 2 1 24t 2 8, where x and t are expressed in inches and seconds,
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Answer:

a)  t = 2.0 s,  b)  x_f = - 24.56 m,  Δx = 16.56 m

Explanation:

This is an exercise in kinematics, the relationship of position and time is indicated

          x = 5 t³ - 9t² -24 t - 8

a) ask when the velocity is zero

speed is defined by

         v = \frac{dx}{dt}

let's perform the derivative

        v = 15 t² - 18t - 24

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let's solve the quadratic equation

      t = \frac{18 \pm \sqrt{18^2 + 4 \ 15 \ 24}  }{2 \ 15}

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the time has to be positive therefore the correct answer is t = 2.0 s

b) the position and distance traveled for a = 0

acceleration is defined by

       a = dv / dt

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       a = 0

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we substitute this time in the expression of the position

       

       x = 5 0.6³ - 9 0.6² - 24 0.6 - 8

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       x = -24.56 m

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      x_f = - 24.56 m

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     ΔX = x_f - x₀

     Δx = | -24.56 -(-8) |

     Δx = 16.56 m

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