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expeople1 [14]
3 years ago
6

Describe the forces that are acting on a person who is standing still on a sidewalk, and identify whether the forces are balance

d or unbalanced. Describe how the forces would change if the person started walking.
Physics
1 answer:
mr_godi [17]3 years ago
6 0

Answer:

a. i His weight and the normal force on him due to the ground

ii The weight and the normal force are balance

b. There are four forces acting on him while he is walking. These are the backward push due to his leg on the ground and the frictional force between his feet in the horizontal direction and, his weight and normal force on his feet in the vertical direction.

Explanation:

a. i Describe the forces that are acting on a person who is standing still on a sidewalk

His weight and the normal force on him due to the ground act on him while the person is standing on the sidewalk

ii. identify whether the forces are balanced or unbalanced.

The weight and the normal force are balance because, the person does not move in the vertical or horizontal direction.

b. Describe how the forces would change if the person started walking.

When the person starts walking, the backward push due to his leg on the ground and the frictional force between his feet and the ground now acts on him in the horizontal direction. The frictional force acts in the forward direction and tends to move him forward. His weight and normal force on his feet still act vertically and are both balanced since he does not move in the vertical direction.

<u>So, there are four forces acting on him while he is walking. These are the backward push due to his leg on the ground and the frictional force between his feet in the horizontal direction and, his weight and normal force on his feet in the vertical direction.</u>

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2 years ago
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kodGreya [7K]

The Impulse delivered to the baseball is 89 kgm/s.

To solve the problem above, we use the formula of impulse.

⇒ Formula:

  • I = m(v-u)................. Equation 1

Where:

  • I = Impulse delivered to the baseball
  • m = mass of the baseball
  • v = Final velocity of the baseball
  • u = initial speed of the baseball

From the question,

⇒ Given:

  • m = 0.8 kg
  • u = 67 m/s
  • v = -44 m/s

⇒ Substitute these values into equation 1

  • I = 0.8(-44-67)
  • I = 0.8(-111)
  • I = -88.8
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Note: The negative tells that the impulse is in the same direction as the final velocity and therefore can be ignored.

Hence, The Impulse delivered to the baseball is 89 kgm/s.

Learn more about impulse here: brainly.com/question/7973509

7 0
2 years ago
Two coconuts fall freely from rest at the same time, one from a tree twice as high as the other. If the coconut from the shorter
valentinak56 [21]

Wee can use here kinematics

as we know that

y = v*t + \frac{1}{2} at^2

for shorter tree we know that

y = 0 + \frac{1}{2}*9.8 * 2^2

y = 19.6 meter

now since we know that other tree is twice high

So height of other tree is y = 39.2 m

now again by above equation

y = v*t + \frac{1}{2} at^2

39.2 = 0 + \frac{1}{2}*9.8 * t^2

t = 2.83 s

so the time taken is 2.83 s

4 0
2 years ago
When tightening a bolt, you push perpendicularly on a wrench with a force of 165 N at a distance of 0.140 m from the center of t
choli [55]

Answer:

Part a)

\tau = 23.1 Nm

Part b)

\tau = 17.05 Foot pound force

Explanation:

As we know that torque is defined as the product of force and its perpendicular distance from reference point

so here we have

\tau = \vec r \times \vec F

now we have

\tau = (0.140)(165)

\tau = 23.1 Nm

Part b)

Now we know the conversion as

1 meter = 3.28 foot

1 N = 0.225 Lb force

now we have

\tau = 23.1 Nm

\tau = 23.1 (0.225 Lb)(3.28 foot)

\tau = 17.05 Foot pound force

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Answer:

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8. False

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