Answer:
Explanation:
The distance of searchlight will act as radius R and velocity of car may be supposed to be tangential velocity v . We are required to calculate angular velocity ω .
v = 80 ft /s
R = 3000 ft
ω = v / R
= 80 / 3000 = .027 rad / s
For angular acceleration the formula is
angular acceleration α = a / R
a is linear acceleration = 15 ft / s²
α = 15 / 3000 = .005 rad / s².
Railroad steel wheels. Bowling ball.
Newton's Third Law of Motion states that for every action there must exist an equal but opposite reaction.
This ultimately implies that, Newton's Third Law of Motion is a law based on action-reaction force pairs.
In this exercise, you're required to identify the action-reaction forces in the attached picture.
Under condition A, a boy is leaning against a wall;
- The force being exerted by the boy on the wall is a force of action.
- The force being exerted by the wall on the boy is a force of reaction.
Under condition B, a boy is jumping off a diving board.
- The force being exerted by the feet of the boy on the diving board is a force of action.
- The force being exerted by the diving board on the feet of the boy is a force of reaction.
Under condition C, a nail is being hammered into the wall.
- The force being exerted by the hammer on the nail is a force of action.
- The force being exerted by the nail on the hammer is a force of reaction.
Under condition D, a man is walking on a ground (floor).
- The force being exerted by the foot of the man on the ground (floor) is a force of action.
- The force being exerted by the ground (floor) on the foot of the man is a force of reaction.
Under condition E, a boy is holding a ball;
- The force being exerted by the hand of the boy on the ball is a force of action.
- The force being exerted by the ball on the hand of the boy is a force of reaction.
Read more: brainly.com/question/15170643
1.) Ohm's law is understood as I = V/R. Given that resistance is constant, then voltage changes directly proportional to current.
2.) The more current that passes through a lightbulb, the brighter it glows. The higher the current, the higher the power, where power determines the brightness of a bulb.
3.) A bulb has a specific limit to how much power (Watts) it can handle. Going over the limit would cause the bulb to burn out.
4.) When a bulb burns out, no current will be able to pass through the filament.
