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Rashid [163]
3 years ago
14

Hi i need help pls help me

Physics
2 answers:
r-ruslan [8.4K]3 years ago
4 0
The correct answer would be the last one
ZanzabumX [31]3 years ago
3 0

Answer:

best answer would be a

Explanation:

d is just a law

c is just the start of a paragraph

and b would be a revision or addtion to the already amendments

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A coin is dropped in a 15.0 m deep well.
labwork [276]

Answer:

t = 1.75

t = 0.04

Explanation:

a)

For part 1 we want to use a kenamatic equation with constant acceleration:

X = 1/2*a*t^2

isolate time

t = sqrt(2X / a)

Plugin known variables. Acceleration is the force of gravity which is 9.8 m/s^2

t = sqrt(2*15m / 9.8m/s^2)

t = 1.75 s

b)

The speed of sound travels at a constant speed therefore we don't need acceleration and can use the equation:

v = d / t

isolate time

t = d / v

plug in known variables

t = 15m / 340m/s

t = 0.04 s

7 0
2 years ago
A car battery can deliver up to 75 amps of current at a voltage of 12 volts. How much power is this?
Alex_Xolod [135]
A.900 watts That would be your correct answer 
4 0
3 years ago
Read 2 more answers
A particle leaves the origin with a speed of 3 106 m/s at 38 degrees to the positive x axis. It moves in a uniform electric fiel
Salsk061 [2.6K]

Answer:

If the particle is an electron E_y = 3.311 * 10^3 N/C

If the particle is a proton, E_y = 6.08 * 10^6 N/C

Explanation:

Initial speed at the origin, u = 3 * 10^6 m/s

\theta = 38^0 to +ve x-axis

The particle crosses the x-axis at , x = 1.5 cm = 0.015 m

The particle can either be an electron or a proton:

Mass of an electron, m_e = 9.1 * 10^{-31} kg

Mass of a proton, m_p = 1.67 * 10^{-27} kg

The electric field intensity along the positive y axis E_y, can be given by the formula:

E_y = \frac{2 m u^2 sin \theta cos \theta}{qx} \\

If the particle is an electron:

E_y = \frac{2 m_e u^2 sin \theta cos \theta}{qx} \\

E_y = \frac{2 * 9.1 * 10^{-31} * (3*10^6)^2 *(sin38)( cos38)}{1.6*10^{-19} * 0.015} \\

E_y = 3311.13 N/C\\E_y = 3.311 * 10^3 N/C

If the particle is a proton:

E_y = \frac{2 m_p u^2 sin \theta cos \theta}{qx} \\

E_y = \frac{2 * 1.67 * 10^{-27} * (3*10^6)^2 *(sin38)( cos38)}{1.6*10^{-19} * 0.015} \\

E_y = 6.08 * 10^6 N/C

8 0
3 years ago
A physicist found that a force of 1.32 N was measured between two charged spheres. The distance between the spheres was 95 cm. C
labwork [276]

The electric force (and the gravitational force too) is inversely proportional
to the square of the distance between the objects involved.

In this question, the distance is increased by a factor of  (1.25/0.95) .

So the electric force will change by the factor of  (0.95/1.25)² .

The new force is

           (1.32 N) · (0.95/1.25)²  =  0.762... newton   (rounded)
5 0
3 years ago
Use this media to help you complete the question.
Papessa [141]

Answer:

589.3 g is the answer

Explanation:

6 0
3 years ago
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