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ivolga24 [154]
3 years ago
9

Assume that two of the electrons at the negative terminal have attached themselves to a nearby neutral atom. There is now a nega

tive ion with a charge -2e at this terminal. What are the electric potential and electric potential energy of the negative ion relative to the electron?
The electric potential and the electric potential energy are both twice as much.
The electric potential is twice as much and the electric potential energy is the same.
The electric potential is the same and the electric potential energy is twice as much.
The electric potential and the electric potential energy are both the same.
The electric potential is the same and the electric potential energy is increased by the mass ratio of the oxygen ion to the electron.
The electric potential is twice as much and the electric potential energy is increased by the mass ratio of the oxygen ion to the electron.
Physics
1 answer:
devlian [24]3 years ago
5 0

Answer: its negative

Explanation: becase it is

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B or 2

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A 110 V power line is protected by a 15 A fuse. What is the maximum number of 400 W lamps that can be simultaneously operated in
Nitella [24]

Answer:

Total number of lamps will be 4            

Explanation:

We have given power of the lamp W = 400 watt

Potential difference across the lamp V=110 volt

We know that power is equal to P=VI

So 400=110\times I

I=3.636A

Total current is given 15 A

As it is given that lamps are connected in parallel so total current is the sum of current through each lamp

So number of lamp will be n=\frac{15}{3.636}=4.125

As the lamp can not be in negative

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3 years ago
The unit used to measure electric current is the ampere (A). Now, assume that the current delivered at a wall socket reaches the
pav-90 [236]

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T = 0.017s

Explanation:

period is the time it takes a particle to make one oscillation

An electric current is periodic in nature

The current reaches 3.8A  ten times.  

So there must have been 10 cycles (10 periods) in 0.17s.   let 'T'  be the period:

T=\frac{t}{n}

t is the total time interval

n is the number of oscillations

T=\frac{0.17}{10}

10T = 0.17

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8 0
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yes

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6 0
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Estimate the volume of a typical house (2050 feet squared in size and 10 feet tall) answer in units of meters squared
Aloiza [94]

Answer:

Volume = 6248.48 m^{3}

Explanation:

Given:

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Solution:

We find the volume of the house by multiplying the area of the house and height of the house.

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Volume = A\times h

Area and height of the house are known, so we substitute these value in above equation.

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Now we convert the unit from feet to meter.

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Volume = \frac{20500}{3.2808}

Volume = 6248.48\ m^{3}

Therefore, the volume of the house is 6248.48 m^{3}

8 0
3 years ago
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