Answer: Partial pressure of 
at a depth of 132 ft below sea level is 2964 mm Hg.
Explanation:
It is known that 1 atm = 760 mm Hg.
Also, 
where, 
= partial pressure of
P = atmospheric pressure
= mole fraction of
Putting the given values into the above formula as follows.
= 0.780
Now, at a depth of 132 ft below the surface of the water where pressure is 5.0 atm. So, partial pressure of is as follows.
= 
= 2964 mm Hg
Therefore, we can conclude that partial pressure of at a depth of 132 ft below sea level is 2964 mm Hg.
Answer:
pH = 10.38
Explanation:
∴ molar mass C9H13N = 135.21 g/mol
∴ pKb = - log Kb = 4.2
⇒ Kb = 6.309 E-5 = [OH-][C9H20O3N+] / [C9H13N]
∴ <em>C</em> sln = (205 mg/L )*(g/1000 mg)*(mol/135.21 g) = 1.516 E-3 M
mass balance:
⇒ <em>C</em> sln = 1.516 E-3 = [C9H20O3N+] + [C9H13N]......(1)
charge balance:
⇒ [C9H20O3N+] + [H3O+] = [OH-]; [H3O+] is neglected, come from water
⇒ [C9H20O3N+] = [OH-].......(2)
(2) in (1):
⇒ [C9H13N] = 1.516 E-3 - [OH-]
replacing in Kb:
⇒ Kb = 6.3096 E-5 = [OH-]² / (1.516 E-3 - [OH-])
⇒ [OH-]² + 6.3096 E-5[OH] - 7.26613 E-8 = 0
⇒ [OH-] = 2.3985 E-4 M
∴ pOH = - Log [OH-]
⇒ pOH = 3.62
⇒ pH = 14 - pOH = 14 - 3.62 = 10.38
Answer:
VC = 18
Explanation:
Since L is the midpoint and you have LV, you know that LC is also 9.
2.5 km is the distance you can travel if a car gets 14 kilometers per liter and have 35 liters of gas.
Total distance traveled in 1 liter = 14 km
Total gas in the car = 35 liters
We have to find how much distance can be covered in in35 liters of gas.
Distance is the length of the path traveled between two points. It is the total movement of an object in a direction. It measures length.
Distance = 35/14
Or, distance = 2.5 km
Therefore, the total distance that can be covered by a car in 35 liters of gas is 2.5 km.
To learn more about distance, visit: brainly.com/question/15172156
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