Answer:
E = 20.03 J
Explanation:
Given that,
The amount of charge that passes through the filament of a certain lightbulb in 2.00 s is 1.67 C,
Voltage, V = 12 V
We need to find the energy delivered to the lightbulb filament during 2.00 s.
The energy delivered is given by :
. ....(1)
As,
As per Ohm's law, V = IR
Using formula (1).
So, the energy delivered to the lightbulb filament is 20.03 J.
Technically, I can't answer the question, because you won't
let me see the picture that goes along with it and is a part of it.
But I'm familiar with the set-up, have dealt with the question before,
and I can answer it from my previous experience and general knowledge.
If there is 500g of mass inside the jar when you lower it over
the candle, then there will be 500g of mass at any time after that,
forever, or until you pick up the jar and take some mass out or put
some more in. It doesn't matter how long you wait. It also doesn't
matter whether or not the candle is burning, whether or not the sun
is shining on the jar, or whether somebody comes along and spray-paints
the outside of the jar with black paint. Matter is not created or destroyed.
Whatever mass was inside when the jar got closed stays in there.
Answer:
2) τ = F x torque increases, 3) troque decreases,
4) man approaches the pivot and the child must move away
5) Σ τ = 0
Explanation:
2) when the man moves away from the pivot his torque increases significantly, since his distance increases
τ = F x
τ = m g x
therefore the system rotates faster
3) when the child approaches the pivot, his troque decreases, because the distance decreases
τ = f x
therefore the system must spin slower
4) If we place the man and the child on the side of a scale, the movement must be the man approaches the pivot and the child must move away, so that the torque is the same and the system can reach a balance
5) the rotational equilibrium expression
Σ τ = 0
is the one that describes the equilibrium of a system with several forces
