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prohojiy [21]
3 years ago
10

At an amusement park, the wheelie carries passengers in a circular path of radius r = 11.2 m. If the angular speed of the wheeli

e is 0.550 revolutions/s, (a) What is the tangential velocity of the passengers due to the circular motion? (b) What is the acceleration of the passengers?
Physics
1 answer:
Dafna1 [17]3 years ago
8 0

Answer:

(a) Tangential velocity will be 38.648 m/sec

(b) Acceleration will be 133.617m/sec^2

Explanation:

We have given radius r = 11.2 m

Angular speed \omega =0.550rev/sec=0.550\times 2\pi =3.454rad/sec

(a) We have to find the tangential velocity

We know that tangential velocity is given by  

v_t=\omega r=3.454\times 11.2=38.684m/sec

(b) We know that acceleration is given by

a=\frac{v^2}{r}=\frac{38.684^2}{11.2}=133.617m/sec^2

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