Question

At an amusement park, the wheelie carries passengers in a circular path of radius r = 11.2 m. If the angular speed of the wheelie is 0.550 revolutions/s, (a) What is the tangential velocity of the passengers due to the circular motion? (b) What is the acceleration of the passengers?

Answer 1

Answer:

(a) Tangential velocity will be 38.648 m/sec

(b) Acceleration will be $133.617m/sec^2$

Explanation:

We have given radius r = 11.2 m

Angular speed $\omega =0.550rev/sec=0.550\times 2\pi =3.454rad/sec$

(a) We have to find the tangential velocity

We know that tangential velocity is given by  

$v_t=\omega r=3.454\times 11.2=38.684m/sec$

(b) We know that acceleration is given by

$a=\frac{v^2}{r}=\frac{38.684^2}{11.2}=133.617m/sec^2$