Supposing that the spring is un stretched when θ = 0, and has a toughness of k = 60 N/m.It seems that the spring has a roller support on the left end. This would make the spring force direction always to the left
Sum moments about the pivot to zero.
10.0(9.81)[(2sinθ)/2] + 50 - 60(2sinθ)[2cosθ] = 0 98.1sinθ + 50 - (120)2sinθcosθ = 0 98.1sinθ + 50 - (120)sin(2θ) = 0
by iterative answer we discover that
θ ≈ 0.465 radians
θ ≈ 26.6º
Answer:
The loop penetrate 4 cm into the magnetic field.
Explanation:
Given that,
Width w= 5 cm
Length L= 10 cm
mass m = 40 g
Resistance R = 20 mΩ
Initial velocity = 1 m/s
Magnetic field = 2 T
We need to calculate the induced emf
Using formula of emf

Put the value into the formula


We need to calculate the current
Using Lenz's formula



We need to calculate the force
Using formula of force


Put the value into the formula


We need to calculate the acceleration
Using formula of acceleration

Put the value in to the formula


We need to calculate the distance
Using equation of motion





Hence, The loop penetrate 4 cm into the magnetic field.
Answer:
See below
Explanation:
a) Spring force at release = k * d = 132 N/m * .120 m = 15.84 N
b) F = ma
15.84 = (.660 kg)(a) a = 24 m/s^2
c) Toward the left ....the object is accelerated to the left
Answer:
It means that if force is constant, as mass is increased, acceleration decreases
Explanation: