Answer:
1837.89 Lt
Explanation:
The chemical reaction for this situation is:
NaHCO₃ + HCl → NaCL + H₂O + CO₂ ₍g₎
Where the mola mass we need are:
M NaHCO₃ = 84 g/mol
M CO₂ = 44 g/mol
As we have 6.00 Kg of sodium bicarbonate, then:
6 Kg NaHCO₃ = 71.43 moles of NaHCO₃
Due the stoichiometry of this chemaicl reaction:
1 mol NaHCO₃ = 1 mol CO₂
71.43 moles NaHCO₃ = 71.43 moles CO₂
And considering that CO₂ is an ideal gas, we can use the following formula:
PV=nRT
V = (nRT)/P
n = 71.43 mol
R = 0.083 Ltxatm(molxK)
T = 37°C = 310 K
P = 1 atm
So: V = (71.43x0.083x310)/1
V CO₂ = 1837.89 Lt
Explanation:
Fe²⁺ + 2e⁻ → Fe
In a reduction half, the oxidizing agent is getting reduced. Such ion is donating electrons.
In a reduction process:
- there is removal of oxygen from a specie
- addition of hydrogen to a specie
- gain of electron by an atom
- decrease in oxidation number of an atom
- decrease in number of electronegative atoms surrounding the element in changing from reactants to products.
Learn more:
Redox reactions brainly.com/question/2890416
#learnwithBrainly
A 3.0 L balloon is 2.5 times as big as a 1.2L balloon, and 3 times .060 equals .18, so if you multiply .18 by 2.5 you get .45 moles of air i’m pretty sure
